将std :: string转换为v8 :: string，反之亦然? [英] Convert std::string to v8::string and viceversa?

问题描述

我正在尝试用c ++创建我的第一个节点模块.我只是想做一个简单的Hello，将我的名字作为参数传递.我发现这种方法可以将参数转换为v8 :: strings，这似乎很丑陋:

i'm trying to create my first node module in c++. I just wanted to do a simple Hello passing my name as parameter. I found this way to convert parameters to v8::strings which seems quite ugly:

Local<String> name = String::NewFromUtf8(isolate, *v8::String::Utf8Value(args[0]->ToString()));

有没有人可以建议我进行这种类型的简单投射?！我想念什么吗?！

Is there anyone who could suggest me simple way to do this sort of cast?! Am i missing something?!

推荐答案

v8的新版本也需要隔离:

Newer versions of v8 requires also isolate:

void Foo(const v8::FunctionCallbackInfo<v8::Value> &args)
{
  // from v8 to cpp
  v8::Isolate* isolate = args.GetIsolate();
  v8::String::Utf8Value str(isolate, args[0]);
  std::string cppStr(*str);

  // back to v8
  v8::Local<v8::String> v8String = v8::String::NewFromUtf8(isolate, cppStr.c_str(), v8::String::kNormalString);
}

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