编写程序以将输入复制到输出 [英] Write a program to copy input to output

问题描述

我正在尝试编写一个将其输入复制到其输出的程序.我假设如果给我以下字符串:"Hello I am/c"，它应该输出:"Hello \ t am \ c"我正确吗?

I am trying to write a program that copies its input to its output. I am assuming that if I am given the following string: "Hello I am /c" it should output: "Hello \t am \c" am I correct?

我尝试过在线阅读有关stdio.h库的信息.

I have tried reading online about the stdio.h library.

#include <stdio.h>
/* Write a program to copy its input to its output, replacing each tab by \t, each backspace by \b, and each backslash by \\. This makes tabs and backspaces visible in an unambigous way.*/

int main()
{
    char c;

    while ((c = getchar()) != EOF){

        if ((c = getchar()) == '\t'){
            putchar('\t');
        }
        if (c == '\b'){
            puts("\b");
        }
        if (c == '\\'){
            puts("\\");
        }

        putchar(c);
    }

}

请帮助我进一步理解这个问题，并解释为什么我的代码不起作用.

Please help me further understand this question and explain why my code does not work.

推荐答案

两个问题.首先:

while ((c = getchar()) != EOF){

您应该将 getchar()的返回值与 EOF 进行比较.在这里，您将 c 与 EOF 进行比较.这是不正确的，因为 c 是 char ，而 getchar 返回 int .因此，您应该将 int 与 EOF 进行比较，并且将 char 与 EOF 进行比较.错了.

You're supposed to compare the return value of getchar() to EOF. Here, you compare c to EOF. That's incorrect because c is a char and getchar returns an int. So you're supposed to be comparing an int to EOF and you are comparing a char to EOF. That's wrong.

第二:

    if ((c = getchar()) == '\t'){

您为什么再次致电 getchar ?您不想读取其他字符.

Why are you calling getchar again? You don't want to read another character.

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