C ++将双精度取整至小数点后2位 [英] C++ round a double up to 2 decimal places

问题描述

我无法将GPA的整数四舍五入到小数点后两位.(例如，需要对GPA进行四舍五入:3.67924)我目前正在使用ceil进行四舍五入，但是目前将其输出为整数(368)

I am having trouble rounding a GPA double to 2 decimal places. (ex of a GPA needed to be rounded: 3.67924) I am currently using ceil to round up, but it currently outputs it as a whole number (368)

这是我现在拥有的

if (cin >> gpa) {
    if (gpa >= 0 && gpa <= 5) {
           // valid number

           gpa = ceil(gpa * 100);

           break;
    } else {
           cout << "Please enter a valid GPA (0.00 - 5.00)" << endl;
           cout << "GPA: ";

    }
}

将上面的代码与3.67924一起使用将输出368(这是我想要的，但是没有整数和小数点之间的句点).我该如何解决?

using the above code with 3.67924 would output 368 (which is what I want, but just without the period between the whole number and the decimals). How can I fix this?

推荐答案

要舍弃小数点后2位小数，可以使用:

To round a double up to 2 decimal places, you can use:

#include <iostream>
#include <cmath>

int main() {
    double value = 0.123;
    value = std::ceil(value * 100.0) / 100.0;
    std::cout << value << std::endl; // prints 0.13
    return 0;
}

要舍入到小数点后n位，您可以使用:

To round up to n decimal places, you can use:

double round_up(double value, int decimal_places) {
    const double multiplier = std::pow(10.0, decimal_places);
    return std::ceil(value * multiplier) / multiplier;
}

这种方法并不是特别快，如果性能成为问题，您可能需要其他解决方案.

This method won't be particularly fast, if performance becomes an issue you may need another solution.

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