球面碰撞解决 [英] Sphere-plane collision resolve

问题描述

我想编写一个c ++程序，该程序将计算球体和平面之间的碰撞.

I want to write a c++ program that will calculate collision between sphere and plane.

规则是下落物体的角度等于反射角度.

The rule is that the angle of the falling object equals to angle of reflection.

我对球有什么看法

//sphere coordinates and radius
float x;
float y;
float z;
float r;
//sphere velocity vector projections
float vx;
float vy;
float vz;

平面由平面方程系数来描述:

Plane is described by plane equation coefficients:

float A;
float B;
float C;
float D;

通过球体平面碰撞检测，我没有问题.但是碰撞后如何求速度呢?

With sphere-plane collision detection I have no problem. But how to find velocity after collision?

我发现了什么

因此，最终我需要计算 vx vy vz 的更新值.

So, ultimately I need to calculate updated values for vx vy vz.

推荐答案

定义平面的方程为

Ax + By + Cz + D = 0

所以垂直于平面的向量是

So the vector normal to the plane is

W = (A, B, C)

归一化:

n = W/|W|

现在获取速度矢量:

V = (vx, vy, vz)

其垂直于飞机的分量是

Vn = (V . n) n

其余部分，与平面平行的部分是

and the rest of it, the part parallel to the plane is

Vp = V - Vn

我们要反转普通分量，并保持并行分量不变:

We want to reverse the normal component and leave the parallel component unchanged:

V' = -Vn + Vp

可以解决

V' = V - 2(V . n)n

这篇关于球面碰撞解决的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！