自动打开在Python中作为命令行参数指定的文件 [英] Automatically open files given as command line arguments in Python

问题描述

我有很多类似于以下内容的Perl脚本.它的作用是它将自动打开作为命令行参数给出的任何文件，在这种情况下，将打印该文件的内容.如果没有给出文件，它将从标准输入中读取.

I have a lot of Perl scripts that looks something like the following. What it does is that it will automatically open any file given as a command line argument and in this case print the content of that file. If no file is given it will instead read from standard input.

while ( <> ) {
    print $_;
}

有没有一种方法可以在Python中执行类似的操作而不必显式打开每个文件?

Is there a way to do something similar in Python without having to explicitly open each file?

推荐答案

The fileinput module in Python's standard library is designed exactly for this purpose, and I quote a bit of code from the URL I just gave:

import fileinput
for line in fileinput.input():
    process(line)

使用 print 代替 process ，您将获得与Perl代码完全相同的内容.

Use print in lieu of process and you have the exact equivalent of your Perl code.

这篇关于自动打开在Python中作为命令行参数指定的文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！