有没有更紧凑的方法来检查数字是否在范围内? [英] Is there a more compact way of checking if a number is within a range?

问题描述

我希望能够测试一个值是否在数字范围内.这是我当前的代码:

I want to be able to test whether a value is within a number range. This is my current code:

if ((year < 2099) && (year > 1990)){
    return 'good stuff';
}

有没有更简单的方法可以做到这一点?例如，有这样的东西吗?

Is there a simpler way to do this? For example, is there something like this?

if (1990 < year < 2099){
    return 'good stuff';
}

推荐答案

在许多语言中，第二种方法将根据您想要的内容从左到右进行错误评估.

In many languages, the second way will be evaluated from left to right incorrectly with regard to what you want.

例如，在C中， 1990<年份的值为0或1，然后变为 1<2099 ，当然总是如此.

In C, for instance, 1990 < year will evaluate to 0 or 1, which then becomes 1 < 2099, which is always true, of course.

Javascript与C非常相似: 1990<year 返回 true 或 false ，这些布尔表达式似乎在数值上分别等于0和1.

Javascript is a quite similar to C: 1990 < year returns true or false, and those boolean expressions seem to numerically compare equal to 0 and 1 respectively.

但是在C#中，它甚至无法编译，从而给您带来错误:

But in C#, it won't even compile, giving you the error:

错误CS0019:运算符'<'不能应用于类型为'bool'和'int'的操作数

error CS0019: Operator '<' cannot be applied to operands of type 'bool' and 'int'

您会从Ruby中收到类似的错误，而Haskell告诉您不能在相同的中缀表达式中两次使用< .

You get a similar error from Ruby, while Haskell tells you that you cannot use < twice in the same infix expression.

在我的脑海中，Python是我确定以这种方式处理中间"设置的唯一语言:

Off the top of my head, Python is the only language that I'm sure handles the "between" setup that way:

>>> year = 5
>>> 1990 < year < 2099
False
>>> year = 2000
>>> 1990 < year < 2099
True

最重要的是，第一个方法(x< y& y< z)始终是您最安全的选择.

The bottom line is that the first way (x < y && y < z) is always your safest bet.

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