无法在Python中定义多个构造函数吗? [英] Is it not possible to define multiple constructors in Python?

问题描述

可能重复:
什么是干净，pythonic的方法在Python中有多个构造函数?

是否无法在Python中用不同的签名定义多个构造函数?如果没有，解决该问题的一般方法是什么?

Is it not possible to define multiple constructors in Python, with different signatures? If not, what's the general way of getting around it?

例如，假设您要定义一个 City 类.

For example, let's say you wanted to define a class City.

我想说 someCity = City()或 someCity = City("Berlin")，其中第一个只是给出默认名称值，第二个定义它.

I'd like to be able to say someCity = City() or someCity = City("Berlin"), where the first just gives a default name value, and the second defines it.

推荐答案

与Java不同，您不能定义多个构造函数.但是，如果未传递默认值，则可以定义默认值.

Unlike Java, you cannot define multiple constructors. However, you can define a default value if one is not passed.

def __init__(self, city="Berlin"):
  self.city = city

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