ListView DisplayMemberPath模板错误? [英] ListView DisplayMemberPath Template Bug?

问题描述

我想知道是否有人对此问题有所了解.看来此处为ListViewItem提供的默认模板不支持 ListView的> DisplayMemberPath .

示例

 < ListView ItemsSource ="{Binding SomeSource}" DisplayMemberPath ="Name"/> 

将不会按预期显示项目.如果将 GridViewRowPresenter 替换为 ContentPresenter ，它将起作用.因此，我编写一个可以正常工作的模板的解决方法是为 DisplayMemberPath 和 Value =" 编写一个DataTrigger，然后将模板设置为包含GridViewRowPresenter的模板.如果我不这样做，使用ItemsPresenter的GroupStyle将不起作用.

我的问题:这是一个错误还是我做错了什么?

解决方案

我在此处

DisplayMemberPath 属性实际上是一个快捷方式，它将告诉WPF创建默认项目模板，而该模板仅包含 TextBlock ，且文本绑定到 DisplayMemberPath

如果除了设置 DisplayMemberPath 之外还覆盖了项目模板，则实际上是在覆盖 DisplayMemberPath 为您创建的模板，因此该属性将变得无用.

I am wondering if anyone know something about this issue. It seems like the default template provided here for ListViewItem does not support DisplayMemberPath of ListView.

Example

<ListView ItemsSource="{Binding SomeSource}" DisplayMemberPath="Name" />

will not display the items as expected. It will work if I replace the GridViewRowPresenter with a ContentPresenter. So my workaround to write a fully working template is to write a DataTrigger for DisplayMemberPath with Value="" and there I set the Template to a Template containing the GridViewRowPresenter. If I will not do this a GroupStyle with ItemsPresenter will not work.

My Question: Is this a bug or am I doing something wrong?

解决方案

I asked a similar question here

The DisplayMemberPath property is actually a shortcut that will tell WPF to create the default item template with nothing more than a TextBlock with it's Text bound to whatever field is in DisplayMemberPath

If you overwrite the item template in addition to setting DisplayMemberPath, then you are essentially overwriting the template that DisplayMemberPath created for you, so that property becomes useless.

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