破解凯撒密码的程序 [英] Program to crack Caesar cipher

问题描述

凯撒密码基本上将每个明文字母移动一个固定数字.例如，如果使用键2，则单词Sourpuss将被编码为Uqwrtrwuu

The Caesar cipher basically shifts each letter of plaintext by a fixed number. For example, if the key 2 is used, the word Sourpuss would be encoded Uqwrtrwuu

文本只能包含可打印的ASCII字符(出于我们的目的，为32-126).实现用于破解此代码的算法.

The text can contain only the printable ASCII characters (32-126, for our purposes). Implement an algorithm for cracking this code.

我需要解密:"T！x $ r&'} r& z！％21j！'1〜zxy& 1"r %% 1TZedBEAB?"

I need to decrypt this: "T! x$r&'}r&z! %21j!'1~zxy&1"r%%1TZedBEAB?"

这是我的代码:

def decoded(s):
    for i in range(1,95):
        string = ""
        for char in s:
            if(ord(char) + i > 126):
                charc = (ord(char) + i) - 94
                string =  string + chr(charc)
            else:
               charc = ord(char) + i
               string =  string + chr(charc) 

        print(string)
decoded("T! x$r&'}r&z! %21j!'1~zxy&1\"r%%1TZedBEAB?")

您可以看到我添加了 \ ，但是我认为这不会改变我的答案吗?

As you can see I added a \ but I don't think that would change my answer?

问题是它没有打印出正确的答案.有人可以告诉我我的代码有什么问题吗，或者只是指出正确的方向.

The problem is that it is not printing out a correct answer. Could someone please tell me what is wrong with my code or just point me in the right direction.

推荐答案

关键#78:恭喜！您可能会通过CITS1401.

Key #78: Congratulations! You might pass CITS1401.

您要做的就是在第6行中将 -94 更改为 -95 .

All you have to do is change -94 to -95 in line 6.

如果您得到127减去94，那么您得到33，而您希望它是32.(正如Antti Haapala指出的那样).

If you get 127 and subtract 94, you get 33, and you want it to be 32. (As Antti Haapala pointed out).

如果您后退并使用 ord(char)-i<32 ，如果为true，则添加95，您将得到Key#17.

If you go backwards and take ord(char) - i < 32, and add 95 if its true, you'll get Key #17 instead.

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