如何为倾斜的边缘使用剪切路径? [英] How can I Use Clip-Path for slanted edges?

问题描述

当前使用此CSS进行从左到右的底部倾斜:

Currently using this CSS for a bottom slant going up from left to right:

clip-path: polygon(    0 0,    100% 0,    100% calc(100% - 3vw),    0 100%  );

它对于响应式解决方案非常有效，但是很难弄清楚如何针对div顶部从左到右倾斜的响应式解决方案执行此操作.

It works very well for a responsive solution but having a hard time figuring out how to do this for a responsive solution for a slant at the top of the div going down from left to right.

我尝试过:

clip-path: polygon(    0 0,    100% calc(100% - 29vw),    100% 100%,    0 100%  );

谢谢！

推荐答案

您可以进行如下调整.您将第二个点从 3vw 开始降低，然后将另一点放回 100％

You can adjust like below. You make the second point to start lower by 3vw and you put back the other one to 100%

.box {
  height: 100px;
  background: red;
  clip-path: polygon( 0 0, 100% 3vw, 100% 100%, 0 100%);
  
  /*    (0,0) ----------------- (100%,0) 
             |                 |<---------(100%,3vw)
             |                 |
             |                 |
             |                 |
     (0,100%) -----------------  (100%,100%)
}

<div class="box">

</div>

如果要从右到左，请按以下步骤操作:

And like this if you want from right to left:

.box {
  height: 100px;
  background: red;
  clip-path: polygon( 0 3vw, 100% 0, 100% 100%, 0 100%);
}

<div class="box">

</div>

侧面:

.box {
  height: 100px;
  background: red;
  clip-path: polygon( 0 0, calc(100% - 3vw) 0, 100% 100%, 0 100%);
}

<div class="box">

</div>

如果您想要一种更受支持的方法，则可以考虑以下多种背景:

If you want a more supported way, you can consider multiple background like below:

.box {
  height: 100px;
  margin:5px;
  padding-top:3vw;
  background: 
   /*a triangle shape on the padding-top area*/
   linear-gradient(to bottom var(--d,left),transparent 48%,red 50%) top/100% 3.1vw no-repeat,
   /*color the content and not the padding-top*/
   linear-gradient(red,red) content-box;
}

<div class="box">

</div>

<div class="box" style="--d:right">

</div>

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