比较两个char *是否相等 [英] Comparing two char* for equality

问题描述

可能重复:
比较两个C-样式字符串?

我的比赛条件不起作用！有人可以建议如何与C风格的字符串进行比较吗?

My match condition doesn't work! Can someone advise how to compare to C-style strings?

void saveData(string line, char* data){
    char *testString = new char[800];
    char *stpr;
    int i=0;
    bool isData=false;
    char *com = data;
    strcpy(testString,line.c_str());
        stpr = strtok(testString, ",");
        while (stpr != NULL) {
            string temp = stpr;
            cout << temp << " ===== " << data << endl;

即使 temp 和 data 匹配，以下条件也不起作用:

Even though temp and data match, the following condition doesn't work:

if (stpr==data) {
  isData = true; 
}

不确定是否有帮助.从以下函数中调用 SaveData()函数:

Not sure if this helps. The SaveData() function is called from the function below:

void readFile(char* str){
    string c="", line, fileName="result.txt", data(str);
        ifstream inFile;
    inFile.open(fileName.c_str());
    resultlist.clear();

    if(inFile.good()){    
        while(!inFile.eof()){
            getline(inFile, line);
            if(line.find(data)!=string::npos){
                cout << line << endl;
            }
            saveData(line, str);
        }
        inFile.close();
    }

}

推荐答案

由于 stpr 和 data 都是C字符串，因此您需要使用

Since both stpr and data are C strings, you need to use strcmp():

#include <string.h>
...
if (strcmp(stpr, data) == 0) {
    // strings are equal
    ...
} else {
    // strings are NOT equal
}

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