更改已加载的csv文件中的定界符 [英] Changing delimiter in a loaded csv file
问题描述
我已经在内存中加载了一个csv文件.我的csv文件使用;"作为字段定界符.
I have loaded a csv file in memory. My csv file uses ";" as the field delimiter.
似乎vba的默认分隔符是,",因为当我尝试访问已加载的csv文件的某些行和列时,vba会优先浏览元素,直到使用的数字为,".
It seems vba default delimiter is "," because when I try to access certain row and column of the loaded csv file, vba advances through the elements with refrence to number of "," used.
示例:
数据的第10行有5列:aa 12,34 bb 5,678(此处的,"是小数点分隔符)
In the 10th row of my data there are five columns: aa 12,34 bb 5,678 (here "," is decimal separator)
在分隔符为;"的csv文件中看起来像这样:
in the csv file which the delimiter is ";" it looks like this:
aa; 12,34; bb; 5,678
aa;12,34;bb;5,678
所以当我写
MyData(10,2)
我期望得到12,34,但是vba返回34; bb; 5,因为它使用,"作为字段定界符.
I am expecting to get 12,34 but vba returns 34;bb;5 because it uses "," as field delimiter.
所以我的问题:
如何告诉vba相对于;"搜索已加载的csv文件?作为分隔符而不是,"?
How can I tell vba to search through the loaded csv file with respect to ";" as delimiter instead of ","?
谢谢.
推荐答案
与其尝试更改excel用于加载csv文件的定界符,不如自行完成
Instead of trying to change the delimiter which excel uses to load a csv file it might be more straightforward to do that on your own
首先,您使用函数将文本文件的行加载到集合中,然后访问该集合中的所需行并转到所需列.
First you use a function to load the lines of a text file into a collection and then you access the wanted line in that collection and go to the wanted column.
此代码
Option Explicit
Function txtfileinCol(filename As String) As Collection
' loads the content of a textfile line by line into a collection
Dim fileContent As Collection
Set fileContent = New Collection
Dim fileNo As Long
Dim txtLine As String
fileNo = FreeFile
Open filename For Input As #fileNo
Do Until EOF(fileNo)
Line Input #fileNo, txtLine
fileContent.Add txtLine
Loop
Close #fileNo
Set txtfileinCol = fileContent
End Function
Sub Testit()
Const DELIMITER = ";"
Dim filename As String
Dim col As Collection
Dim vdat As Variant
Dim colNo As Long
Dim rowNo As Long
filename = "C:\Temp\FILE.csv"
Set col = txtfileinCol(filename)
colNo = 2
rowNo = 10
vdat = col.Item(rowNo) 'here you get the line you want
vdat = Split(vdat, DELIMITER) ' now you split the line with the DELIMITER you define
Debug.Print vdat(colNo - 1) ' now you print the content of the column you want
End Sub
更新:要访问行和列,您还可以使用一个功能.代码看起来像这样
Update: For accessing the row and column you could also use a function. The code would look like that
Option Explicit
Function txtfileinCol(filename As String) As Collection
' loads the content of a textfile line by line into a collection
Dim fileContent As Collection
Set fileContent = New Collection
Dim fileNo As Long
Dim txtLine As String
fileNo = FreeFile
Open filename For Input As #fileNo
Do Until EOF(fileNo)
Line Input #fileNo, txtLine
fileContent.Add txtLine
Loop
Close #fileNo
Set txtfileinCol = fileContent
End Function
Function getColRow(fileLines As Collection, rowNo As Long, colNo As Long, Optional delimiter As String) As String
Dim vdat As Variant
On Error GoTo EH:
If Len(delimiter) = 0 Then
delimiter = ";"
End If
vdat = fileLines.Item(rowNo) 'here you get the line
vdat = Split(vdat, delimiter) 'now you split the line with the delimiter
getColRow = vdat(colNo - 1) 'now you retrieve the content of the column
Exit Function
EH:
getColRow = ""
End Function
Sub Testit()
Dim filename As String
Dim col As Collection
filename = "C:\Temp\FILE.csv"
Set col = txtfileinCol(filename)
Debug.Print getColRow(col, 10, 2, ";")
End Sub
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