Python ctypes CFofType的地址 [英] Python ctypes addressof CFuncType

问题描述

与我的其他问题

如何获取CFuncType对象的地址(虚拟函数指针)?addressof()没有报告正确的地址.

How can I get the address (acctual function pointer) to a CFuncType object? addressof() does not report the correct address.

C代码:

extern "C" _declspec(dllexport)
int addr(int (*func)())
{
    int r = (int)func;
    return r;
}

Python代码:

def test():
  return 42

t = CFUNCTYPE(c_int)
f = t(test)

print addressof(f)
print dll.addr(f)

输出:

7030864
3411932

尝试从C调用*(7030864)会导致崩溃，但是调用*(3411932)会按预期工作.addressof()有什么问题?

trying to call *(7030864) from C causes a crash, but calling *(3411932) works as expected. What's wrong with addressof()?

推荐答案

cast(f，c_void_p)从python内部获取正确的地址

cast(f, c_void_p) gets the correct address from within python

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