从B页返回时，如何刷新A页上的小部件? [英] How can i refresh the widget on the the page A, when i return from page B?

问题描述

我有一个有状态的Page A，其中包含一个小部件，该小部件存在于单独的有状态类中.

I have a stateful Page A that contains a widget which is present in a seperate stateful class.

该小部件在其initState方法中从sharedPreferences中获取一个数字并显示出来，当我单击该小部件时，它会路由到Page B，Page B包含一个用于更改sharedPreferences中数字的函数.

The widget fetches a number from sharedPreferences in its initState method and show it and when i click on the widget, it routes to Page B, Page B contains a function that change the number in the sharedPreferences.

当我返回时，我看不到更改，但是当我重新打开应用程序或切换到其他选项卡并返回时，我会看到.

when i go back i dont see the changes but when i reopen the app or switch to a different tab and come back, i do.

推荐答案

在A页中，当您转到B页时，

In page A, when you go to page B use,

Navigator.pushNamed(context, "/pageB").then((value) {
  if (value == true) {
    setState(() {
      // refresh page 1 here, you may want to reload your SharedPreferences here according to your needs
    });
  }
});

在B页中，当您想返回到A页时，请使用

In page B, when you want to go back to page A, use

Navigator.pop(context, true);

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编辑:如果您没有命名路线，则可能需要在第一种情况下使用关注.

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Edit: If you don't have a named route, you may want to use following in 1st situation.

Navigator.push(context, MaterialPageRoute(builder: (context) => PageB())).then((value) {
  if (value == true) {
    setState(() {
      // refresh page 1 here, you may want to reload your SharedPreferences here according to your needs
    });
  }
});

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