如何接收XML请求，并在PHP发送响应XML？ [英] How to receive xml requests and send response xml in php?

问题描述

所以，我需要建立将接收XML请求，并根据我将不得不返回响应XML的应用程序。我知道如何发送请求和接收响应，但我从来没有做过的其他方式。我会发送请求，像这样：

So I need to build an application that will receive xml request and based on that I will have to return the response xml. I know how to send requests and receive the response, but I have never done it the other way. I would send the request like so:

private function sendRequest($requestXML)
{
    $server = 'http://www.something.com/myapp';
    $headers = array(
    "Content-type: text/xml"
    ,"Content-length: ".strlen($requestXML)
    ,"Connection: close"
    );

    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_URL, $server);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_TIMEOUT, 100);
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $requestXML);
    curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    $data = curl_exec($ch);



    if(curl_errno($ch)){
        print curl_error($ch);
        echo "  something went wrong..... try later";
    }else{
        curl_close($ch);
    }

    return $data;

}

我的问题是 - 什么将是对接收方的code？我如何赶上传入的请求？
谢谢你。

My question is - what would be the code on the receiving side? How do I catch the incoming request? Thanks.

推荐答案

的总体思路是按照API您在POST值读取，解析为XML，就成为一个商业决策，打造出了一个XML响应已经决定上，并将其写入到响应。

The general idea is to read in the POST value, parse it as XML, make a business decision on it, build out an XML response according to the API you've decided on, and write it into the response.

阅读中的POST值：

$dataPOST = trim(file_get_contents('php://input'));

解析为XML：

$xmlData = simplexml_load_string($dataPOST);

然后，你就打造出了一个XML字符串（或文档树，如果你愿意的话），并打印出来到响应。打印（）或回波（）会做得很好。

Then, you would build out an XML string (or document tree, if you wish), and print it out to the response. print() or echo() will do fine.

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