编写最小-最大缩放器功能 [英] Writing Min-Max scaler function

问题描述

我想在python中编写一个用于计算最小-最大比例的函数，以返回列表.

I want to write a function for calculating Min-Max scale in python that return a list.

x = [1, 2, 3, 4]

def normalize(x):

    for i in range(len(x)):
        return [(x[i] - min(x)) / (max(x) - min(x))]

然后调用该函数:

normalize(x):

结果:

[0.0]

我期望结果是:

[0.00, 0.33, 0.66, 1.00] 

推荐答案

基于@shehan的解决方案:

Based on @shehan's solution:

x = [1, 2, 3, 4]

def normalize(x):
    return [round((i - min(x)) / (max(x) - min(x)), 2) for i in x]

print(normalize(x))

完全给您您想要的.与其他解决方案不同，结果经过了四舍五入(这就是您想要的).

gives you exactly what you wanted. The result is rounded up unlike other solutions (as that's what you wanted).

结果:

[0.0, 0.33, 0.67, 1.0]

答案的循环版本，以便op可以理解:

For loop version of the answer so that op could understand:

x = [1, 2, 3, 4]

def normalize(x):
    # A list to store all calculated values
    a = []
    for i in range(len(x)):
        a.append([(x[i] - min(x)) / (max(x) - min(x))])
        # Notice I didn't return here
    # Return the list here, outside the loop
    return a

print(normalize(x))

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