如何在Python中使用Datetime进行每分钟打印 [英] How can I print every minute using Datetime with Python

问题描述

作为一个例子，我想使用时间或日期时间每过1分钟就打印"1分钟".我不能使用time.sleep(60)，因为我有更多的代码需要在每次更新的whileloop中运行.我需要一种方法来检查datetime.now()是否大于1分钟前.谢谢！

As an example, I want to print, "1 min", every time 1 minute has passed using time or datetime. I cant use time.sleep(60) because I have more code that needs to run in the whileloop every update. I need a way to check if datetime.now() is greater than 1 minute ago. Thanks!

import time
import datetime as dt

t = dt.datetime.now()

while True:
  if 60 seconds has passed:
     print("1 Min")

推荐答案

这可能是您想要的:

import datetime as dt
from time import sleep

t = dt.datetime.now()
minute_count = 0 

while True:
    delta_minutes = (dt.datetime.now() -t).seconds / 60                
    if delta_minutes and delta_minutes != minute_count:
        print("1 Min has passed since the last print")
        minute_count = delta_minutes
    sleep(1) # Stop maxing out CPU

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