在C中的深度复制数组... malloc? [英] Deep copying array in C... malloc?

问题描述

我正在尝试在C中复制数组的深层副本(原始板是副本):

I'm trying to make a deep copy of an array in C (originalBoard being the copy):

int gy, gx;          
            for (gy=0; gy<9; gy++)
            {
                for (gx=0; gx<9; gx++)
                {                  
                g.originalBoard[gy][gx]=g.board[gy][gx];
                }
            }

这似乎没有解决，我猜测这只是指向原始板阵列的指针.

This does not seem to be working out, and I'm guessing this is just making pointers to the original board array.

那么解决方案是尝试使用malloc吗?喜欢:

So would the solution be to try and use malloc? Like:

    int* g.originalBoard[9][9]=malloc(sizeof(g.board[9][9]));

顺便说一句，这是一个9x9的二维数组.语法是什么(编译器在上一行中给出了错误...)?

btw this is a 9x9 two dimensional array. What would the syntax be (the compiler gives an error for the above line...)?

推荐答案

我认为您需要这个:

 //assuming g.originalBoard is array of array of integers and same for g.board  
int *originalBoard = malloc(sizeof(g.board));
memcpy(originalBoard, g.board, sizeof(g.board));

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