如何在python字典的每个键中计算不同值的平均值? [英] How can I calculate average of different values in each key of python dictionary?

问题描述

我有字典.我想计算每个键的平均值并打印结果，以便结果显示键和相关的平均值.以下代码计算平均值，但我不知道如何将键与平均值关联.我想要的答案是Mean = {22:average1，23:average2，24:average3}.

I have a dictionary. I want to calculate average of values for each key and print result so that the result shows key and associated average. The following code calculates mean but I don't know how to associate key with the average. My desired answer is Mean = {22:average1, 23:average2, 24:average3}.

          mydict = {22: [1, 0, 0, 1], 23: [0, 1, 2, 1, 0], 24: [3, 3, 2, 1, 0]}

          Mean =[float(sum(values)) / len(values) for key, values in 
          mydict.iteritems()]

推荐答案

不要使用列表推导.使用字典理解来计算每个列表的平均值.您也可以<__>来自__future__导入部门，以避免必须使用 float :

Don't use a list comprehension. Use a dictionary comprehension to calculate the average of each list. You can also from __future__ import division to avoid having to use float:

>>> from __future__ import division
>>> d = {22: [1, 0, 0, 1], 23: [0, 1, 2, 1, 0], 24: [3, 3, 2, 1, 0]}
>>> mean = {k: sum(v) / len(v) for k, v in d.iteritems()}
>>> mean
{22: 0.5, 23: 0.8, 24: 1.8}

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