使用字典的Django分页,其中键是列表 [英] Django pagination with dictionary where key is a list
问题描述
我的 views.py
文件中有一个字典,其中的值是列表.在我的模板中,我有以下html:
I have a dictionary in my views.py
file where the values are lists. In my template I have the following html:
{% for key, values in my_dict %}
<tr>
<td colspan="6" class="key">{{ key }}</td>
</tr>
{% for value in values %}
<tr>
<td colspan="6" class="value">{{ value }}</td>
</tr>
{% endfor %}
{% endfor %}
会打印出键的名称,后跟值中的列表项.但是,我希望能够对键进行分页,以便每页仅显示10个键及其值.
which prints out the name of the key followed by the list items inside the value. However, I want to be able to paginate the keys such that only 10 keys with their values appear per page.
我有以下代码在 views.py
中的 index
方法中进行分页:
I have the following code to do the pagination inside my index
method in views.py
:
paginator = Paginator(myDict, 10)
page_num = requests.GET.get('page', 1)
page = paginator.page(page_num)
我将模板更新为 {%键,页面%中的值}
,当然,我收到TypeError,因为它是可哈希的类型.我只是想知道如何才能产生与以前相同的结果,却不使用字典.
I updated my template to {% for key, values in page %}
and of course I get a TypeError because it's a hashable type. I'm just wondering how I can go about producing the same results as before but without using a dictionary.
我找到了此答案,建议改用元组的字典,但这似乎对我不起作用,我猜是因为我的值是列表.
I found this answer that suggests using tuples instead of dictionaries, but that doesn't seem to work for me and I'm guessing because my values are lists.
推荐答案
我不确定是否可以算是一个好答案,但是无论如何:我只是想用 tuple
并且有效.因此,我认为问题可能出在您的代码中.我的测试代码:
I am not sure if it can be count as good answer but anyway: I have just tried to replicate your problem and solution with tuple
and it worked. So I think the problem can be in your code. My test code:
>>> from django.core.paginator import Paginator
>>> d = {'a': [1,2], 'b': [3,4]}
>>> p = Paginator(d, 1)
>>> p1 = p.page(1)
Traceback (most recent call last):
File "<input>", line 1, in <module>
TypeError: unhashable type
>>> t = tuple(d.items())
>>> t
(('a', [1, 2]), ('b', [3, 4]))
>>> p = Paginator(t, 1)
>>> p.page(1).object_list
(('a', [1, 2]),)
>>> p.page(2).object_list
(('b', [3, 4]),)
更新:和循环也可以.那你能证明你有什么结构吗?
UPDATE: and looping also works. So can you show what structures do you have?
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