Python Dict超过一个Max值 [英] Python Dict more than one Max value

问题描述

我正在使用列表使用以下行从列表中的一组项目中找到最大值: x = max(dictionary，key = dictionary.get)除非字典中的两个或多个值相同，否则此方法工作正常，似乎只是在完全随机的情况下选择了最大值之一.有没有一种方法可以打印两个最大值，可能在列表中，例如: dictionary = {'A':2，'B':1，'C':2} ，它将返回 x = ['A'，'C']

I am using a list to find a max value from a group of items in the list using the line: x=max(dictionary, key=dictionary.get) This works fine unless two or more values in the dictionary are the same, it just seems to choose one of the max at complete random. Is there a way that I can get it to print both of the max values, possibly in a list eg:dictionary={'A':2,'B':1,'C':2} which will return x=['A','C']

推荐答案

>>> dictionary = { 'A': 2, 'B': 1, 'C': 2 }
>>> maxValue = max(dictionary.values())
>>> [k for k, v in dictionary.items() if v == maxValue]
['C', 'A']

您还可以使用计数器来获取按最常见"(最高值)排序的项目:

You can also use a counter to get the items sorted by "most common" (highest value):

>>> from collections import Counter
>>> c = Counter(dictionary)
>>> c.most_common()
[('C', 2), ('A', 2), ('B', 1)]

不幸的是，参数 n 到 most_common 可以为您提供 n 个最大元素，而并非所有元素都具有最大值，因此您需要过滤手动，例如使用 itertools.takewhile :

Unfortunately, the parameter n to most_common gives you n maximum elements, and not all with the maximum value, so you need to filter them manually, e.g. using itertools.takewhile:

>>> from itertools import takewhile
>>> maxValue = c.most_common(1)[0][1]
>>> list(takewhile(lambda x: x[1] == maxValue, c.most_common()))
[('C', 2), ('A', 2)]

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