如何将参数从Makefile传递到程序? [英] How to pass argument from Makefile to a program?

问题描述

我想将Makefile目录传递给函数.

I want to pass directory of Makefile to a function.

例如:

Makefile

$(DIR)=生成文件目录

程序

int main(int argc，char argv [])char目录= argv [1]

我该怎么办?

编辑澄清.我希望我的应用程序可以在我将其编译到的目录之外运行.

EDIT Clarificaion. I want my app to work outside of the directory that i compiled it in.

推荐答案

在编译时通过-D选项传递符号(示例是C ++，但是您可以轻松地转换为C).您可以只定义符号，也可以给它一个值(这就是您想要的值).

Passing a symbol at compile time is done with the -D option (example is C++ but you can transpose to C easily). You can either only define the symbol, or give it a value (which is what you want here).

DIR=$(shell pwd)
mytarget: 
    @echo "DIRECTORY=$(DIR)"
    $(CXX) mysource.cpp -D"DIRECTORY=$(DIR)" -o mysource

然后，在源文件中，符号 DIRECTORY 将包含路径.要对此进行检查，您需要一个额外的技巧(称为双重扩展"):

Then, in your source file, the symbol DIRECTORY will hold the path. To check this, you need an additional trick (known as "double expansion"):

#define STR1(x)  #x
#define STR(x)  STR1(x)
#include <iostream>
int main()
{
    std::cout << "directory is " << STR(DIRECTORY) << "\n";
}

您可以检查此类似问题和

You can check this similar question, and see here about the D flag.

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