如何根据给定的要求自动拆分列表? [英] How can I automatically split a list up based on a given requirement?

问题描述

在Discord上，您只能接收字符长度为2000或以下的消息.我试图将僵尸程序所在的每个服务器的服务器名称，成员数量和服务器ID附加到列表中，然后将该列表发送到频道.

On Discord, you can only have messages of character length 2000 or under. I am trying to append the server name, member amount and server ID for each server that the bot is in to a list, and then sending the list to a channel.

但是，当列表长度超过2000时，我试图将其拆分，但是该方法要求每次列表变大时都必须手动对其进行更新.如何使脚本根据需要的分割数"自动分割列表，然后发送这些分割数"?

However, as the list length exceeds 2000 I have tried to split it up, however the method requires it to be updated every time manually as the list gets larger. How can I make the script automatically split up the list based on how many 'splits' are required and then send those 'splits'?

到目前为止，我可以运行，但是不是自动的:

What I have so far, which works, but is not automatic:

@commands.command()
async def getallservers(self, ctx):
    serverslist = []

    def split_list(alist, wanted_parts=1):
        length = len(alist)
        return [ alist[i*length // wanted_parts: (i+1)*length // wanted_parts] 
                for i in range(wanted_parts) ]

    if ctx.author.id == 204616460797083648:
        for x in self.bot.guilds:
            serverslist.append(f'{x.name}: **{len(x.members)}** - {x.id}\n')

        q1,q2,q3,q4,q5,q6 = split_list(serverslist, wanted_parts=6)

        embed = discord.Embed(title='Server List')

        embed.description = ''.join(q1)
        await ctx.send(embed=embed)
        embed.description = ''.join(q2)
        await ctx.send(embed=embed)
        embed.description = ''.join(q3)
        await ctx.send(embed=embed)
        embed.description = ''.join(q4)
        await ctx.send(embed=embed)
        embed.description = ''.join(q5)
        await ctx.send(embed=embed)
        embed.description = ''.join(q6)
        await ctx.send(embed=embed)
    else:
        pass

推荐答案

一个拥有 serverslist 的人，可以将其传递给构建<2000个字符页面

One you have the serverslist, you can pass it to a function that builds < 2000 character pages

def paginate(lines, chars=2000):
    size = 0
    message = []
    for line in lines:
        if len(line) + size > chars:
            yield message
            message = []
            size = 0
        message.append(line)
        size += len(line)
    yield message

然后在您的命令中

for message in paginate(serverlist):
    embed.description = ''.join(message)
    await ctx.send(embed=embed)

这篇关于如何根据给定的要求自动拆分列表?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！