Django REST框架+ Django REST Swagger + ImageField [英] Django REST Framework + Django REST Swagger + ImageField
问题描述
我用ImageField创建了一个简单的模型,我想用django-rest-framework + django-rest-swagger制作一个api视图,该文档已被记录并能够上传文件.
I created a simple Model with an ImageField and I wanna make an api view with django-rest-framework + django-rest-swagger, that is documented and is able to upload the file.
这就是我得到的:
models.py
models.py
from django.utils import timezone
from django.db import models
class MyModel(models.Model):
source = models.ImageField(upload_to=u'/photos')
is_active = models.BooleanField(default=False)
created_at = models.DateTimeField(default=timezone.now)
def __unicode__(self):
return u"photo {0}".format(self.source.url)
serializer.py
serializer.py
from .models import MyModel
class MyModelSerializer(serializers.ModelSerializer):
class Meta:
model = MyModel
fields = [
'id',
'source',
'created_at',
]
views.py
views.py
from rest_framework import generics
from .serializer import MyModelSerializer
class MyModelView(generics.CreateAPIView):
serializer_class = MyModelSerializer
parser_classes = (FileUploadParser, )
def post(self, *args, **kwargs):
"""
Create a MyModel
---
parameters:
- name: source
description: file
required: True
type: file
responseMessages:
- code: 201
message: Created
"""
return super(MyModelView, self).post(self, *args, **kwargs)
urls.py
urls.py
from weddings.api.views import MyModelView
urlpatterns = patterns(
'',
url(r'^/api/mymodel/$', MyModelView.as_view()),
)
对我来说,这应该很简单.但是,我无法进行上传.我总是收到以下错误响应:
For me this should be pretty simple. However, I can't make the upload work. I always get this error response:
我已经从 django-rest阅读了文档的这一部分-框架:
如果使用文件名URL关键字参数调用与FileUploadParser一起使用的视图,则该参数将用作文件名.如果在没有文件名URL关键字参数的情况下调用该文件,则客户端必须在Content-Disposition HTTP标头中设置文件名.例如Content-Disposition:附件;filename = upload.jpg.
但是django-rest-swagger在Request Payload属性(从chrome控制台)中传递了Header.
However the Header is being passed by django-rest-swagger in the Request Payload property (from chrome console).
如果需要更多信息,请告诉我.
If any more info is necessary, please let me know.
我正在使用 Django == 1.8.8
, djangorestframework == 3.3.2
和 django-rest-swagger == 0.3.4 代码>.
推荐答案
这是我想出的最终解决方案:
This is the final solution I came up with:
from rest_framework import generics
from rest_framework.parsers import FormParser, MultiPartParser
from .serializer import MyModelSerializer
class MyModelView(generics.CreateAPIView):
serializer_class = MyModelSerializer
parser_classes = (FormParser, MultiPartParser)
def post(self, *args, **kwargs):
"""
Create a MyModel
---
parameters:
- name: source
description: file
required: True
type: file
responseMessages:
- code: 201
message: Created
"""
return super(MyModelView, self).post(self, *args, **kwargs)
我要做的就是将解析器从 FileUploadParser
更改为(FormParser,MultiPartParser)
All I had to do was change the parsers from FileUploadParser
to (FormParser, MultiPartParser)
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