Django在发布图像创建函数视图中出现类型错误 [英] Django getting Type error in post image create function view

问题描述

下面的代码出错了 TypeError:post_image_create()缺少1个必需的位置参数:'post'我想在表单提交之前异步将多个图像添加到Django表单中.我有Javascript代码用于在客户端上载图像并将其异步添加到我的服务器.我要做的就是给它一个端点

The code below is getting error TypeError: post_image_create() missing 1 required positional argument: 'post' I want to add multiple images to a django form asynchronously before form submit.I have the Javascript code for uploading of the images on the client side and asynchronously adds it to my server. All I need to do is give it a endpoint

我将不胜感激.

模型

class FileModel(models.Model):
    post = models.ForeignKey(Article, on_delete=models.CASCADE)
    file = models.FileField(upload_to='stories', blank=True, null=True)

观看次数

def post_image_create(request, post):
    if(request.method == "POST"):
        for f in request.FILES.getlist('file'):
            FileModel.objects.create(file=f)


class NewsCreateView(CreateView):
    form_class = FileForm
    template_name = 'news/news_create.html'
    success_url = '/'

    def form_valid(self, form):
        post = form.save(commit=False)
        post.author = self.request.user
        post_image_create(request=self.request, post=post)  # This function is defined above
        post.save()
        return super().form_valid(form)

推荐答案

这是说您的请求函数缺少参数. TypeError:post_image_create()缺少1个必需的位置参数:"post" .

This is saying that your request function is missing an argument. TypeError: post_image_create() missing 1 required positional argument: 'post'.

在视图函数中，您定义了 def post_image_create(request，post):，但在urls.py中将其设置为: path('new_image/'，views.post_image_create，名称="new_image")如果要传递参数，则需要在urls.py url路由器中进行设置.

In your view function, you define def post_image_create(request, post): but in your urls.py you have it set up as :path('new_image/', views.post_image_create, name='new_image') If you want to pass a parameter you need to set set that up in your urls.py url router.

但不用于传递帖子数据.您可以使用请求对象访问帖子数据.将视图功能更改为:

BUT that isn't used for passing post data. You can access post data using the request object. Change your view function to be:

def post_image_create(request):
  if(request.method == "POST"):
    files = request.FILES 
     ...then do stuff

它在文档中: https://docs.djangoproject.com/zh-CN/3.1/ref/request-response/#django.http.HttpRequest.method

以及有关将urls.py中的参数传递给视图函数的更多信息:

and more about passing parameter in urls.py to a view function: https://docs.djangoproject.com/en/3.1/topics/http/urls/#example

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