docker run -e无法正常工作，发生错误了吗? [英] docker run -e not working, bug?

问题描述

根据文档:

此外，操作员可以在容器通过使用一个或多个-e标志，甚至覆盖那些标志上面提到的，或者已经由开发人员使用Dockerfile定义ENV.如果操作员在不指定名称的情况下命名环境变量值，则传播已命名变量的当前值进入容器的环境:

Additionally, the operator can set any environment variable in the container by using one or more -e flags, even overriding those mentioned above, or already defined by the developer with a Dockerfile ENV. If the operator names an environment variable without specifying a value, then the current value of the named variable is propagated into the container’s environment:

$ export today=Wednesday
$ docker run -e "deep=purple" -e today --rm alpine env
PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin
HOSTNAME=d2219b854598
deep=purple
today=Wednesday
HOME=/root

我试图用我的容器运行docker run -e:

I tried to run docker run -e with my container:

docker run -d -it myimage123 -e "myvar=blah"

我收到此错误:

[FATAL tini (7)] exec -e failed: No such file or directory

推荐答案

尝试:

docker run -d -it -e"myvar = blah" myimage123

这里的问题是 -e 是一个标志，而 myimage123 是一个参数.因此，参数应始终位于标志之后.

The problem here is that -e is a flag and myimage123 is an argument. So the arguments should always come after the flags.

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