在C ++中使用多个条件的While循环 [英] While loop with multiple conditions in C++

问题描述

我如何制作一个循环，直到满足多个条件之一为止.例如:

 做{srand(time(0));estrength = rand()％100);srand(time(0));强度= rand()％100);} while()//力量或力量都不等于100 

有一个la脚的例子，但我想大家都会明白的.

我知道&& ;，但我希望它只满足其中一个条件并继续前进，不能同时满足这两个条件.

解决方案

使用 || 和/或&& 运算符组合您的条件./p>

示例:

1.

 做{...} while(a || b); 

将在 a 或 b 为真时循环.

2.

 做{...} while(a&& b); 

当 a 和 b 为真时，

将循环.

How would I make a loop that does the loop until one of multiple conditions is met. For example:

do
{
    srand (time(0));
    estrength = rand()%100);

    srand (time(0));
    strength = rand()%100);
} while( ) //either strength or estrength is not equal to 100

Kind of a lame example, but I think you all will understand.

I know of &&, but I want it to only meet one of the conditions and move on, not both.

解决方案

Use the || and/or the && operators to combine your conditions.

Examples:

1.

do
{
   ...
} while (a || b);

will loop while either a or b are true.

2.

do
{
...
} while (a && b);

will loop while both a and b are true.

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