如何随机在蛇上打洞? [英] How can I randomly make holes in snake?
问题描述
我有一条正在转弯并在其后面绘制轨迹的蛇，但是我不知道如何在绘制时像随机停顿一样打洞.我试过了，它不是随机的，但问题是停顿非常快.这就像传送移动.这是我的代码:
import pygamepygame.init()随机导入来自随机进口randint赢= pygame.display.set_mode((1280,720))背景= pygame.Surface(win.get_size()，pygame.SRCALPHA)background.fill((0，0，0，1))x = randint(150,1130)y = randint(150,570)vel = 0.6drawing_time = 0方向= pygame.math.Vector2(vel，0).rotate(random.randint(0，360))运行=真运行时:pygame.time.delay(5)drawing_time + = 1如果drawing_time == 1000:对于范围(0，60)的暂停:头= pygame.draw.circle(win，(255,0,0)，(round(x)，round(y))，0)键= pygame.key.get_pressed()如果键[pygame.K_LEFT]:direction.rotate_ip(-0.8)如果键[pygame.K_RIGHT]:direction.rotate_ip(0.8)x + =方向.xy + =方向时间= 0键= pygame.key.get_pressed()如果键[pygame.K_LEFT]:direction.rotate_ip(-0.8)如果键[pygame.K_RIGHT]:direction.rotate_ip(0.8)x + =方向.xy + = direction.ywin.blit(背景(12020,0))head = pygame.draw.circle(win，(255,0,0)，(round(x)，round(y))，5)pygame.display.update()pygame.quit() 我试图将头部半径设为0，也许这是个问题，但我不知道如何解决.
永远不要在应用程序循环中实现控制游戏的循环.您需要应用程序循环.使用它！
使用
import pygamepygame.init()随机导入来自随机进口randint赢= pygame.display.set_mode((1280,720))背景= pygame.Surface(win.get_size()，pygame.SRCALPHA)background.fill((0，0，0，1))时钟= pygame.time.Clock()x = randint(150,1130)y = randint(150,570)vel = 0.6drawing_time = 0next_change_time = 0draw_snake = False方向= pygame.math.Vector2(vel，0).rotate(random.randint(0，360))运行=真运行时:clock.tick(60)对于pygame.event.get()中的事件:如果event.type == pygame.QUIT:运行=错误current_time = pygame.time.get_ticks()如果current_time>next_change_time:next_change_time =当前时间+ random.randint(500，1000)draw_snake =不是draw_snake键= pygame.key.get_pressed()如果键[pygame.K_LEFT]:direction.rotate_ip(-0.8)如果键[pygame.K_RIGHT]:direction.rotate_ip(0.8)x + =方向.xy + =方向win.blit(背景(12020,0))如果draw_snake:pygame.draw.circle(win，(255,0,0)，(round(x)，round(y))，5)pygame.display.update()pygame.quit() 如果需要其他尺寸的孔，则需要附加条件和不同的随机时间:
如果current_time>next_change_time:draw_snake =不是draw_snake如果draw_snake:next_change_time =当前时间+ random.randint(500，1000)别的:next_change_time =当前时间+ random.randint(250，500) I have snake that is turning and drawing trajectory behind him but I don't know how to make holes like random pauses while he's drawing. I tried it and it's not random but problem is that it's very fast pause. It's like teleporting move. Here is my code:
import pygame
pygame.init()
import random
from random import randint
win = pygame.display.set_mode((1280,720))
background = pygame.Surface(win.get_size(), pygame.SRCALPHA)
background.fill((0, 0, 0, 1))
x = randint(150,1130)
y = randint(150,570)
vel = 0.6
drawing_time = 0
direction = pygame.math.Vector2(vel, 0).rotate(random.randint(0, 360))
run = True
while run:
pygame.time.delay(5)
drawing_time += 1
if drawing_time == 1000:
for pause in range(0, 60):
head = pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 0)
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
direction.rotate_ip(-0.8)
if keys[pygame.K_RIGHT]:
direction.rotate_ip(0.8)
x += direction.x
y += direction.y
time = 0
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
direction.rotate_ip(-0.8)
if keys[pygame.K_RIGHT]:
direction.rotate_ip(0.8)
x += direction.x
y += direction.y
win.blit(background, (12020,0))
head= pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 5)
pygame.display.update()
pygame.quit()
I tried to give that head radius 0 and maybe that is problem but I don't have any idea how to solve it.
Never implement a loop that controls the game in the application loop. You need application loop. Use it!
Use pygame.time.get_ticks() to return the number of milliseconds since pygame.init() was called. Add a variable that indicates whether or not the snake needs to be drawn (draw_snake). Define a variable that indicates the time when the status needs to be changed (next_change_time ). When the time has expired, change the status of the variable and define a new random time at which the status must be changed again. Only draw the snake when the variable is set. this causes holes in the snake:
next_change_time = 0
draw_snake = False
run = True
while run:
# [...]
current_time = pygame.time.get_ticks()
if current_time > next_change_time:
next_change_time = current_time + random.randint(500, 1000)
draw_snake = not draw_snake
# [...]
if draw_snake:
pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 5)
# [...]
Use pygame.time.Clock to control the frames per second and thus the game speed.
The method tick() of a pygame.time.Clock object, delays the game in that way, that every iteration of the loop consumes the same period of time.
That means that the loop:
clock = pygame.time.Clock() run = True while run: clock.tick(60)
runs 60 times per second.
Complete example:
import pygame
pygame.init()
import random
from random import randint
win = pygame.display.set_mode((1280,720))
background = pygame.Surface(win.get_size(), pygame.SRCALPHA)
background.fill((0, 0, 0, 1))
clock = pygame.time.Clock()
x = randint(150,1130)
y = randint(150,570)
vel = 0.6
drawing_time = 0
next_change_time = 0
draw_snake = False
direction = pygame.math.Vector2(vel, 0).rotate(random.randint(0, 360))
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
current_time = pygame.time.get_ticks()
if current_time > next_change_time:
next_change_time = current_time + random.randint(500, 1000)
draw_snake = not draw_snake
keys = pygame.key.get_pressed()
if keys[pygame.K_LEFT]:
direction.rotate_ip(-0.8)
if keys[pygame.K_RIGHT]:
direction.rotate_ip(0.8)
x += direction.x
y += direction.y
win.blit(background, (12020,0))
if draw_snake:
pygame.draw.circle(win, (255,0,0), (round(x), round(y)), 5)
pygame.display.update()
pygame.quit()
If you want other size for the holes you need, additional condition and different random time:
if current_time > next_change_time:
draw_snake = not draw_snake
if draw_snake:
next_change_time = current_time + random.randint(500, 1000)
else:
next_change_time = current_time + random.randint(250, 500)
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