做一个POST请求 [英] Make a POST request

问题描述

我想知道如何使一个HTTP POST请求喜欢它的有<一个描述href=\"http://$c$c.google.com/apis/documents/docs/3.0/developers_guide_protocol.html#UploadingMetadata\" rel=\"nofollow\">http://$c$c.google.com/apis/documents/docs/3.0/developers_guide_protocol.html#UploadingMetadata （创建一个空文件）。
我的code是这样的：

 ＆LT; PHP$头=阵列（
    POST /供稿/默认/私营/全HTTP / 1.1，
    主持人：docs.google.com
    的GData-版本：3.0，
    内容长度：287
    内容类型：应用程序/原子+ XML
）;$数据=＆LT; XML版本='1.0'编码='UTF-8'＆GT;？
$数据=＆LT;入境的xmlns =HTTP：//www.w3.org/2005/Atom'>。
$数据=＆LT;类计划=HTTP：//schemas.google.com/g/2005#kind'。
$数据=一词=的http：//schemas.google.com/docs/2007#document'/>。
$数据=＆LT;标题＆gt;新建文件＆LT; /标题＆gt;中。
$数据=＆LT; /进入＆gt;中;$ CH = curl_init（）;    curl_setopt（$ CH，CURLOPT_URLhttp://google.com/docs/feeds/default/private/full）;
    curl_setopt（$ CH，CURLOPT_POST，真正的）;
    curl_setopt（$ CH，CURLOPT_POSTFIELDS，$数据）;
    curl_setopt（$ CH，CURLOPT_HTTPHEADER，$头）;
    curl_setopt（$ CH，CURLOPT_RETURNTRANSFER，真正的）;
    curl_setopt（$ CH，CURLOPT_HEADER，真正的）;$结果= curl_exec（$ CH）;的print_r（$结果）;？＆GT;
 

有什么不对呢？我在做正确的请求？

解决方案

  $数据=＆LT; XML版本='1.0'编码='UTF-8'＆GT;？ ;
 

替换为：

  $数据=LT;XML版本='1.0'编码='UTF-8'？。＆gt;中;
 

和...

  $ =数据一词=的http：//schemas.google.com/docs/2007#document'/>。
 

使用：

  $ =数据一词=的http：//schemas.google.com/docs/2007#document'/>。
 

---

呵呵，最后，你不应该的print_r ING的结果; 的print_r 是数组和对象，而不是字符串（curl_exec返回一个字符串或空/假），而使用的var_dump（$结果）;

I would like to know how to make a HTTP POST request like it's described there http://code.google.com/apis/documents/docs/3.0/developers_guide_protocol.html#UploadingMetadata (Creating an empty document). My code looks like this:

<?php

$headers = array(
    "POST /feeds/default/private/full HTTP/1.1",
    "Host: docs.google.com",
    "GData-Version: 3.0",
    "Content-Length: 287",
    "Content-Type: application/atom+xml"
);

$data = "<?xml version='1.0' encoding='UTF-8'?>";
$data .= "<entry xmlns='http://www.w3.org/2005/Atom'>";
$data .= "<category scheme='http://schemas.google.com/g/2005#kind'";
$data .= "term='http://schemas.google.com/docs/2007#document'/>";
$data .= "<title>new document</title>";
$data .= "</entry>";

$ch = curl_init();

    curl_setopt($ch, CURLOPT_URL, "http://google.com/docs/feeds/default/private/full");
    curl_setopt($ch, CURLOPT_POST, true);
    curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
    curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_HEADER, true);

$result = curl_exec($ch);

print_r($result);

?>

What's wrong there? Am I doing request correctly?

解决方案

$data = "<?xml version='1.0' encoding='UTF-8'?>";

Replace with:

$data = "<"."?xml version='1.0' encoding='UTF-8'?".">";

And...

$data .= "term='http://schemas.google.com/docs/2007#document'/>";

With:

$data .= " term='http://schemas.google.com/docs/2007#document'/>";

---

Oh and finally, you shouldn't be print_ring the result; print_r is for arrays and objects, not strings (curl_exec returns a string or null/false), instead use var_dump($result);

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