如何在erlang中格式化带有整数的扁平字符串? [英] How to format a flat string with integers in it in erlang?

问题描述

在erlang中，我想格式化其中包含整数的字符串，并且希望将结果展平.但我明白了:

In erlang, I want to format a string with integers in it and I want the result to be flattened. But I get this:

io_lib:format("sdfsdf ~B", [12312]).                 
[115,100,102,115,100,102,32,"12312"]

通过使用下面的代码，我可以得到所需的结果，但它确实不是很优雅.

I can get the desired result by using the code below but it is really not elegant.

lists:flatten(io_lib:format("sdfsdf ~B", [12312])).
"sdfsdf 12312"

是否存在更好的格式设置为整数的字符串，以便它们是扁平的?理想情况下，仅使用一个功能?

Is there a better formatting strings with integers in them, so that they are flat? Ideally, using only one function?

推荐答案

您可以像在示例中一样使用 lists:flatten/1 来扁平化列表.

You flatten a list using lists:flatten/1 as you've done in your example.

如果您可以接受二进制文件，那么 list_to_binary/1 会非常有效:

If you can accept a binary, list_to_binary/1 is quite efficient:

1> list_to_binary(io_lib:format("sdfsdf ~B", [12312])).
<<"sdfsdf 12312">>

但是，请问为什么首先需要一个固定清单.如果只是化妆品，则不需要它. io:format/1,2,3 和大多数其他端口功能( gen_tcp 等)接受所谓的深层IO列表(带有字符和二进制文件的嵌套列表):

However, question why you need a flat list in the first place. If it is just cosmetics, you don't need it. io:format/1,2,3 and most other port functions (gen_tcp etc) accept so called deep IO lists (nested lists with characters and binaries):

2> io:format([115,100,102,115,100,102,32,"12312"]).
sdfsdf 12312ok

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