C ++异常会阻止内联函数吗? [英] Would C++ exception stops function from being inlined?

问题描述

假设我有一个非常简单的函数，希望编译器对其进行内联.但是我可能需要在看到一些无效输入时抛出异常，这会阻止编译器内联函数吗?

Suppose I have a very simple function that I expect the compiler to inline it. But I may need to throw exception on seeing some invalid input, would that stop the compiler from inlining the function?

推荐答案

编译器可以出于任何原因拒绝内联.gcc列出了它可能不内联函数的原因，但不会引发异常他们之中.同样，如果选项-Winline无法内嵌标记为内联的函数，则会导致编译器发出警告.您可以尝试一下，看看您是否正在采取任何措施来防止内联.

A compiler can refuse to inline for any reason. gcc lists reasons why it might not inline a function, but exception throwing is not among them. Also, the option -Winline will cause the compiler to issue a warning if it can't inline a function that you marked as inline. You can try that and see if you are doing anything to prevent inlining.

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