FParsec在可选解析器上失败 [英] FParsec failing on optional parser
问题描述
我目前正在学习FParsec库,但是遇到了一个问题.当我想解析可选字符串并在以后继续正常解析时,FParsec将在可选解析器上返回致命错误,而不是像我期望的那样返回 None
.下面的工作代码示例阐明了我的观点:
I am currently learning the FParsec library, but I have come across an issue. When I want to parse an optional string and continue parsing as normal afterwards, FParsec will return a fatal error on the optional parser, rather than returning None
as I expect. The below working code sample illustrates my point:
open System
open FParsec
type AccountEntity =
| Default
| Entity of string
let pEntity =
let isEntityFirstChar c = isLetter c
let isEntityChar c = isLetter c || isDigit c
(many1Satisfy2L isEntityFirstChar isEntityChar "entity") .>> skipString "/"
let pOptEntity =
opt pEntity
|>> (fun optEntity ->
match optEntity with
| Some entity -> Entity entity
| None -> Default)
[<EntryPoint>]
let main argv =
printfn "%A" (run pOptEntity "test/account:subaccount") //works
printfn "%A" (run pOptEntity "account:subaccount") //crashes
Console.ReadLine() |> ignore
0 // return an integer exit code
我期望的行为是,当未提供实体时, pOptEntity
返回一个 Default
实体.但是,相反,出现以下错误:
The behavior I would expect is for pOptEntity
to return a Default
entity when an entity is not provided. However, instead, I get the following error:
Failure:
Error in Ln: 1 Col: 8
account:subaccount
^
Expecting: '/'
opt
不能提供我正在描述的行为,并继续正常解析帐户字符串,还是我以不正确的方式处理此问题?我查看了 attempt
,但是,那么,我将无法提供所需的默认实体行为.
Shouldn't opt
provide the behavior I am describing and continue to parse the account string as normal or am I approaching this in the incorrect manner? I took a look at attempt
but, then, I wouldn't be able to provide the default entity behavior like I want.
非常感谢您的帮助.
推荐答案
< |>
文档,它提到如果第一个解析器失败而未更改解析器状态,则会尝试第二个解析器. http://www.quanttec.com/fparsec/users-guide/parsing-alternatives.html 进行了更详细的介绍.
The opt
combinator follows the same rules as <|>
; if you look at the <|>
documentation, it mentions that if the first parser fails without changing the parser state, the second parser is attempted. http://www.quanttec.com/fparsec/users-guide/parsing-alternatives.html goes into more detail.
在这里, ./code>组合器
是您要在 pEntity
解析器中使用的.将.>>
替换为.>>?
,您将拥有一个 pEntity
解析器,如果不遵循的话通过/
进行操作,将回溯到尝试执行的内容,并且不会消耗任何输入.这将允许 opt
组合器按设计运行.
Here, the .>>?
combinator is what you want to use in your pEntity
parser. Replace the .>>
with .>>?
and you'll have a pEntity
parser that, if it is not followed by a /
, will backtrack to the beginning of what it attempted and not consume input. This will allow the opt
combinator to function as designed.
PS .我对此进行了测试,并成功了.在 pEntity
中用.>>>?
替换.>>
,然后运行您的代码,将产生以下输出:
P.S. I tested this, and it worked. Replacing the .>>
with .>>?
in pEntity
and then running your code produced the following output:
Success: Entity "test"
Success: Default
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