为什么在这个简单的F#示例中未收集弱引用? [英] Why does the weak reference not get collected in this simple F# example?
问题描述
open System
let WeakReferenceExample() =
let mutable obj = new Object();
let weak = new WeakReference(obj);
GC.Collect();
Console.WriteLine("IsAlive: {0}\nobj <> null is {1}\n---", weak.IsAlive, obj <> null);
obj <- null;
GC.Collect();
Console.WriteLine("IsAlive: {0}", weak.IsAlive);
WeakReferenceExample()
Console.ReadKey()
从 Rx有效书籍样本.上面的运行时提供了以下输出,与我在C#中编译并运行它后得到的输出不同.
Translated from the Rx In Action book sample. The above when run gives the following output which is different than what I get when I compile it in C# and run it.
IsAlive: True
obj <> null is True
---
IsAlive: True
为什么不收集弱引用?
推荐答案
这是测量影响结果的情况之一.
This is one of those cases where the measurement affects the result.
根本原因是在调试过程中优化了编译器(反向?)以实现更好的本地化.
The underlying cause is compiler (reverse?) optimizations for better locals during Debugging.
撰写时:
let list1 = [1; 2; 3]
let list2 = [3; 4; 5]
printfn "%b" (list1 = list2)
这详细说明了每个子表达式:
This elaborates every sub-expression to:
let list1 = [1; 2; 3]
let list2 = [3; 4; 5]
let list1' = list1
let list2' = list2
let is_eq = list1'.Equals(list2')
printfn "%b" (is_eq)
现在您可以开始猜测它的去向了.
Now you can begin to guess where this is going.
Console.WriteLine("IsAlive: {0}\nobj <> null is {1}\n---", weak.IsAlive, obj <> null);
致力于:
let isAlive = weak.IsAlive
let obj' = obj
let isNotNull = obj' <> null
Console.WriteLine("IsAlive: {0}\nobj <> null is {1}\n---", isAlive, isNotNull);
现在,当您这样做时:
obj <- null;
GC.Collect();
请注意, obj'
中仍然存在引用.
note that a reference still exists in obj'
.
因此,在GC传递期间将不会收集对象.这就是 WeakReference
所显示的.
So the object won't be collected during the GC pass.
And that's what WeakReference
is showing.
足够有趣的是,如果注释掉第一个 Console.Writeline
,则没有子表达式的详细说明,因此也没有引用,您将得到:
So interestingly enough, if you comment out the first Console.Writeline
, there's no sub-expression elaboration, hence no references, and you get:
IsAlive: False
或者您也可以以发布模式构建它.
Or you could just build it in Release mode.
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