搜索按扩展名过滤的文件返回太多结果 [英] Searching files filtering by extension returns too many results

问题描述

我正在开发一个必须在Windows OS上管理文件的C ++控制台应用程序.我需要获取具有特定扩展名的文件名的列表".我找到了很多解决方案，最建议的解决方案是以下一种:

I'm developing a C++ console application that has to manage files on Windows OS. I need to obtain a 'list' of file names which have a specific extension. I've found a lot of solutions, the most suggested one is the following one:

HANDLE hFind;
WIN32_FIND_DATA data;

hFind = FindFirstFile("C:\\PWS\\*.sda", &data);
if (hFind != INVALID_HANDLE_VALUE) {
    do {
        cout << data.cFileName << endl;

    } while (FindNextFile(hFind, &data));
    FindClose(hFind);
}

假设我在 C:\\ PWS 文件夹中有这些文件:

Suppose I have these files inside the C:\\PWS folder:

• f001.sdac
• f002.sda
• f003.sdab
• f004.sda

上面的代码将全部打印出来，而我只需要 f002.sda 和 f004.sda .

The above code prints all of them, while I only need f002.sda and f004.sda.

有任何提示吗?

NB :我不想使用Boost库.

NB: I don't want to use boost library.

推荐答案

我采用的解决方案如下:

The solution I adopted is the following one:

void GetFilesByNameRootAndExtension(const string& dirPath, const string& nameRoot, string& ext, vector<string>& files)
{
    files.clear();

    stringstream ss;
    ss << dirPath << "\\" << nameRoot << "*" << ext;
    string searchKeyS = ss.str();
    const char* searchKey = searchKeyS.c_str();

    WIN32_FIND_DATA data;
    HANDLE hFind = FindFirstFile(searchKey, &data);

    ext = ext.erase(0, 1);
    if (hFind != INVALID_HANDLE_VALUE) {
        do {
            string fN = data.cFileName;
            if (fN.substr(fN.find_last_of(".") + 1) == ext) // filtering by extension
                files.push_back(fN);
        } while (FindNextFile(hFind, &data));
        FindClose(hFind);
    }
}

谢谢大家的提示！

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