如何从txt.readlines()中提取数据? [英] How to extract data from a txt.readlines()?

问题描述

我有一个似乎读取文件的小问题的代码...但是问题是它无法识别单词/字母，这就是我的意思. extract('test.txt'，('A'，'E'，'I'，'O'，'U')) test.txt 是txt文件，而('A'，'E'，'I'，'O'，'U')是我要查找的单词.

I have a code that seems to have a slight issue it reads the file... But the issue is it can not identify the words/letters this is what i mean extract('test.txt',('A','E','I','O','U')) the test.txt is a txt file and the ('A','E','I','O','U') is the words i want to find.

我的代码:

def extract(file,find=()):
  with open(str(file),'r') as file:
    find = list(find)
    read_file = file.readlines()
    
    num1 = 0
    num = num1-1
    for vals in find:
      num1 += 1
    pass  
  
    for finds in read_file:
      linef = str(finds)
      main_obj = find[num]
        
      if main_obj in linef:
        print("Yay")
        
      elif linef != main_obj:
        print("NO")
        
      else:
          print("???")
    pass  


extract('test.txt',('A','E','I','O','U'))

我的输出是什么

NO
NO
NO
NO
Yay

这是预期的输出:

Yay
Yay
Yay
Yay
Yay

内部 test.txt :

A
E
I
O
U

推荐答案

我将在此保留.如果最终结果是将 find 内的每个变量与 file 中的每一行进行比较，那么这应该可以完成:

I'll just leave this here. If the end result is to compare each variable inside of find to each line in file then this should do the job:

def extract(file, find=()):
    with open(file) as F:
        contents = F.readlines()

    for line in contents:
        if any([i in line for i in find]):
            print("Yay")
        else:
            print("NO")

extract("test.txt", ('A','E','I','O','U'))

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