使用url参数上传PHP文件 [英] PHP File Upload using url parameters
本文介绍了使用url参数上传PHP文件的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
是否可以使用php和参数中的文件名(而不是使用提交表单)将文件上传到服务器，就像这样:
Is there a way to upload a file to server using php and the filename in a parameter (instead using a submit form), something like this:
myserver/upload.php?file = c:\ example.txt
我正在使用本地服务器，因此文件大小限制或上载功能没有问题，并且我有使用表单上载文件的代码
Im using a local server, so i dont have problems with filesize limit or upload function, and i have a code to upload file using a form
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "DTD/xhtml1-transitional.dtd">
<html>
<body>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" name="fileForm" enctype="multipart/form-data">
File to upload:
<table>
<tr><td><input name="upfile" type="file"></td></tr>
<tr><td><input type="submit" name="submitBtn" value="Upload"></td></tr>
</table>
</form>
<?php
if (isset($_POST['submitBtn'])){
// Define the upload location
$target_path = "c:\\";
// Create the file name with path
$target_path = $target_path . basename( $_FILES['upfile']['name']);
// Try to move the file from the temporay directory to the defined.
if(move_uploaded_file($_FILES['upfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['upfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
}
?>
</body>
感谢您的帮助
推荐答案
Image Upload Via url:
//check
$url = "http://theonlytutorials.com/wp-content/uploads/2014/05/blog-logo1.png";
$name = basename($url);
try {
$files = file_get_contents($url);
if ($files) {
$stored_name = time() . $name;
file_put_contents("assets/images/product/$stored_name", $files);
}
}catch (Exception $e){
}
这篇关于使用url参数上传PHP文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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