使用sed/bash删除左右方括号 [英] Remove Left and right square brackets using sed/bash

问题描述

我有一个字符为 [Contributor] 的文件.即贡献者和勇士们在一起

I have a file with this character [Contributor]. I.e the contributor and the bracess all together

我需要使用以下代码将其删除:

I need to remove it using the code below:

find . -type f -exec sed -i 's@ [Contributor]@@g' {} +

任何想法，我如何结合find和sed来实现.或其他任何想法.必须除去开括号和闭括号以及贡献者一词谢谢

Any Idea how I might achive this with find and sed combined. Or any other idea. the open and closed braces must be removed as well as the word contributor Thanks

推荐答案

如果我对您的理解正确，那么此命令应该可以帮助您

If i understood you correctly this command should help:

sed -i 's/\[Contributor\]//g'

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