使用Swift在Firebase中让孩子们的孩子 [英] Get Children of Children in Firebase Using Swift

问题描述

我有一个简单的firebase数据库，我需要从中获取子级值.如何获取子级字段值?这是我的数据库:

I have a simply firebase database that I need to get the children values from. How can I obtain the children field values? Here is my database:

Users

 -LddrOHGdBf_GcPrcvYn

    FirstName: Mike

    LastName: Smith

    username: [e-mail]

我到处都是堆栈溢出，似乎没有人回答这个问题，但是我知道这一定很容易.

I have been all over stack overflow and nothing seems to answer this question, but I know it must be easy.

import UIKit
import FirebaseDatabase

class CustProfileViewController: UIViewController {
var ref: DatabaseReference?
var tempName = ""
var tempFirstName = ""
@IBOutlet weak var username: UITextField!
@IBOutlet weak var firstName: UITextField!
@IBOutlet weak var editAddressButton: UIButton!
override func viewDidLoad() {
    super.viewDidLoad()
    ref = Database.database().reference()
    username.text = "[e-mail]"
}

@IBAction func editAddressButtonPressed(_ sender: Any) {
    self.ref?.child("Users").queryOrdered(byChild: "username").queryEqual(toValue: username.text!).observe(.value, with: { (snapShot) in
        if (snapShot.value! is NSNull) {
        print("nothing found")
    } else {
        print("found it!")
            print(snapShot)
            let snapShotValue = snapShot.value as! NSDictionary
            let fName = snapShotValue["FirstName"] as? String
            self.firstName.text = fName
            print(self.firstName.text!)

        }
    })
}

}

我希望firstName文本框填充fName，但它返回的是nil值.

I am expecting the firstName text box to be populated with the fName, but it is returning a nil value.

推荐答案

您可以尝试

@IBAction func editAddressButtonPressed(_ sender: Any) {
    self.ref?.child("Users").queryOrdered(byChild: "username").queryEqual(toValue: username.text!).observe(.value, with: { (snapShot) in
    if !snapShot.exists() {
         print("nothing found")
    } else {
        print("found it!")
            print(snapShot)
            let snapShotValue = snapShot.value as! [String:[String:Any]]
            Array(snapShotValue.values).forEach {
               let fName = $0["FirstName"] as! String 
               print(fName)
            }

        }
    })
}

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