如何将多个模板传递给flask.render_template() [英] How to pass multiple templates to flask.render_template()
问题描述
我正在尝试部署flask应用程序，并且我希望将flask.render_template()方法与html文件列表一起传递.在这里，我看到它是合格的. http://flask.pocoo.org/docs/0.12/api/#flask.render_template
I'm trying to deploy a flask app and I want a flask.render_template() method passed with a list of html files. Here I see it's eligible. http://flask.pocoo.org/docs/0.12/api/#flask.render_template
我正在尝试使用此代码
from flask import Flask, render_template
app = Flask(__name__)
app.debug = True
@app.route('/')
def hello():
templs = ["_header.html", "_footer.html"]
return render_template(templs)
if __name__== '__main__':
app.run()
但是实际上服务器仅返回列表中的第一个模板.如何遍历此列表以呈现列表中的所有模板?
But actually server returns only the first template from the list. How to iterate though this list in order to render all templates from the list?
谢谢，亚历克斯
推荐答案
据我所知，您正在尝试呈现静态页眉和页脚.我建议准备类似"layout.html"的内容，并附带页眉和页脚:
As far as i see you are trying to render static header and footer. I'd recommend to prepare something like "layout.html" with included header and footer:
//layout.html
<html>
<head>//headhere</head>
<header>//your static header</header>
<main>
{% block body %}
//content will be here
{% endblock %}
</main>
<footer> //your static footer </footer>
</html>
然后在子"模板(例如:index.html)中使用:
then in "child" templates(ex: index.html)use:
//index.html
{% extends "layout.html" %}
{% block body %}
//your code here
{% endblock %}
它将从layout.html渲染页眉和页脚，并从index.html渲染其余页.
It will render header and footer from layout.html and rest from index.html.
这篇关于如何将多个模板传递给flask.render_template()的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
