搜索期间访问Flask-Sqlalchemy查询中的表变量 [英] Accessing table variables in Flask-Sqlalchemy query during search
问题描述
我正在使用Flask和Flask-SQLalchemy以及Flask-Login编写RESTful api.我有一个初始化为 Users
的模型,例如:
I am writing a RESTful api using Flask and Flask-SQLalchemy, as well as Flask-Login. I have a model Users
that's initialized like:
class Users(UserMixin, db.Model):
__tablename__ = "users"
# STATIC Standard required info
id = db.Column("id", db.Integer, primary_key = True)
public_id = db.Column("public_id", db.String(50), unique = True)
email = db.Column("email", db.String(50), unique = True)
username = db.Column("username", db.String(20), unique = True)
password = db.Column("password", db.String(20))
# DYNAMIC Standard required info
lat = db.Column("lat", db.Float)
lon = db.Column("lon", db.Float)
表中还有其他元素,但是lat和lon最相关.我有一个方法 distanceMath()
,该方法接受当前登录用户的纬度和经度,以及表格中的纬度和经度,以计算它们之间的距离.但是我无法弄清楚如何在以下调用 distanceMath
的查询中访问表值而又没有收到语法错误:
There are other elements in the table but the lat and lon are most relevant. I have a method distanceMath()
that takes in the currently logged in user's latitude and longitude, as well as a latitude and longitude from the table to calculate distance between them. But I can't figure out how to access the table values during the following query that calls distanceMath
without receiving a syntax error:
lat1 = current_user.lat
lon1 = current_user.lon
users = Users.query.filter(distanceMath(lat1, Users.lat, lon1, Users.lon)==1)
output = []
for user in users:
data = {}
data["username"] = user.username
output.append(data)
return str(output)
以防万一,这是 distanceMath
方法:
# Haversine Distance
def distanceMath(lat1, lat2, lon1, lon2):
distance = math.acos(math.sin(math.radians(lat1))*math.sin(math.radians(lat2))) + math.cos(math.radians(lat1))*math.cos(math.radians(lat2))*math.cos(math.radians(lon1)-math.radians(lon2))
return distance
错误的示例是:
TypeError: must be real number, not InstrumentedAttribute
在我的理解中,这实际上是在说 User.lat
和 User.lon
并不是指浮点数,甚至不是数字,而是一个属性到桌子上.我的问题是如何实际使用等于lat和lon的值(在数据库中分别等于37.7和-122.4).
Which, in my understanding, is essentially saying that User.lat
and User.lon
don't refer to a float or even a number, and instead an attribute to a table. My question is how to actually use what lat and lon are equal to (In the database they are equal to 37.7 and -122.4 respectively).
推荐答案
我通过采用distanceMath函数并将其放入我的Users模型类中并将其传递给"self"和"math",以及引用表值:
I solved it by taking the distanceMath function and placing it into my Users model class and passing it "self" and "math", as well as referring to the table values accordingly:
def distanceMath(self, lat1, lon1, math=math):
distance = math.acos(math.sin(math.radians(lat1))*math.sin(math.radians(self.lat))) + math.cos(math.radians(lat1))*math.cos(math.radians(self.lat))*math.cos(math.radians(lon1)-math.radians(self.lon))
return distance
然后在执行查询时,只需将current_user传递为Users实例,一切都将正常运行:
Then when performing the query, just pass in the current_user as the Users instance, and everything works perfectly:
users = Users.query.filter(current_user.distanceMath(lat1, lon1) == 1).all()
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