使用Brightscript通过两个文本框和按钮保持焦点 [英] Maintain Focus with two textbox and button using Brightscript

查看:54
本文介绍了使用Brightscript通过两个文本框和按钮保持焦点的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在明亮的脚本中创建了一个登录表单".正在关注

''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''

TextBox 1 '这里的焦点是活动的,我默认在TextBox字段中设置active = true

文本框2 '在这里按下键激活true

按钮1 '再次按下此键可将焦点对准真

''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''

在这里,我使用3个不同的键维护3个项目.现在,我想使用向下键为所有3个项目维护单个键.任何人都想知道如何使用Brightscript保持焦点.

我使用了一个函数来进行键处理

 函数onKeyEvent(键为String,按Boolean)为Boolean........终端功能 

现在,我保持了像我在默认情况下将TextBox Focus设置为XML File,现在将Logic应用于下面.默认情况下,第一项重点放在XML文件上.

 如果key ="down"则'这里第二项重点m.keypass.active = true'在这里成功工作第一次如果key ="down"并且m.keypass.active = true和m.btnsub.active = false,则这里没有成功保持直接呼叫,我按下向下键.m.keypass.active =假m.btnsub.active = true'此处未保持第三项焦点万一万一 

我第一次按下向下键,效果很好,但是第二次如何处理Focus.我在向上键中使用了相同的内容.

在这里我使用"and",那么如果有任何想法,问题就会发生.

请检查一下这是我真正想做的图像.

编辑后的帖子:

我用下面的代码使用向上和向下键进行处理.它正在工作,但是,它一次只能工作.

 如果key ="up"或key ="down"如果键=向下"?这里按下键"如果m.keypass.id ="instructpass"和m.keypass.active = true?按下键,如果有的话"m.btngrp.setFocus(true)m.keypass.active =假处理=真否则,如果m.keyid.id ="instructid"并且m.keyid.active = true?向下键其他部分"m.keypass.active = truem.keyid.active = false处理=真否则,如果m.btngrp.buttonSelected = 0m.keyid.active = truem.btngrp.setFocus(false)处理=真万一处理=真否则,如果key ="up"?这里键"如果m.keypass.active = true?向上键(如果有)"m.keyid.active = truem.keypass.active =假处理=真否则,如果m.keyid.active = true?"ID键"m.btngrp.setFocus(true)m.btngrp.focusButton = 1m.keyid.active = false处理=真否则,如果m.btngrp.focusButton = 0和m.btngrp.buttonSelected = 0?上调键其他部分"m.keypass.active = truem.keypass.setFocus(true)m.btngrp.setFocus(false)处理=真万一处理=真万一处理=真万一 

谢谢.

解决方案

检查此处.

您应该使用.setFocus(true)和.hasFocus(),它们可用于大多数可渲染节点,例如TextEditBox和Button.

例如

 如果key ="down"则如果textBox1.hasFocus()然后textBox2.setFocus(true)elseif textBox2.hasFocus()然后button.setFocus(true)万一万一如果key ="up",则如果button.hasFocus()然后textBox2.setFocus(true)elseif textBox2.hasFocus()然后textBox1.setFocus(true)万一万一 

I created a one Login Form in the bright script. It's following

'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''

TextBox 1 ' Here the focus is active I set by default in TextBox field active = true

TextBox 2 ' Here the press down key to active true

Button 1 ' Here again press down key to focus true

'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''

Here, I maintain the 3 Items using 3 different key. Now I want to maintain the single key for all 3 items using the down key. Anyone idea to How to maintain Focus using Brightscript.

I used the one function for key handling It's here

function onKeyEvent(key as String, press as Boolean) as Boolean

.................

end function

Now, I maintained the key like I set TextBox Focus active in ByDefault to XML File.Now I apply Logic to below. First item focus set on XML file by default.

if key = "down" then 
       'Here Second item focus
       m.keypass.active = true ' Here work successfully First time
       if key = "down" and m.keypass.active = true and m.btnsub.active = false then
          'Here not maintain successfully its directly call here I press the down key.       
           m.keypass.active = false    
           m.btnsub.active = true 'Here third item focus is not maintained 

       end if
end if

I first-time press the down key It's working fine But its second time How handling the Focus. I used the same thing in Up key.

Here I am using "and" then the issue will happen is there any idea.

Pls, Check Here's an image really what I want to do.

Edited Post:

I handle with up and down key with below code. It's working But, Its only work in a single time.

 if key = "up" or key = "down"  
        if key = "down" 

          ?"here down key"

            if m.keypass.id = "instructpass" and m.keypass.active = true
                  ? "down key if part"
                  m.btngrp.setFocus(true)
                  m.keypass.active = false         
                  handled = true
            else if m.keyid.id = "instructid" and m.keyid.active = true 
                ?" down key else part"     
                m.keypass.active = true
                m.keyid.active = false
                handled = true
            else if m.btngrp.buttonSelected = 0
                m.keyid.active = true
                m.btngrp.setFocus(false)
                handled = true              
            end if 

            handled = true

       else if key = "up" 

         ? "here up key"

           if  m.keypass.active = true
                  ?"up key if part"
                  m.keyid.active = true
                  m.keypass.active = false
                  handled = true
           else if  m.keyid.active = true
                  ?"id key"
                  m.btngrp.setFocus(true)
                  m.btngrp.focusButton = 1
                  m.keyid.active = false        
                  handled = true

           else if m.btngrp.focusButton = 0 and m.btngrp.buttonSelected = 0
                ?"up key else part"
                m.keypass.active = true
                m.keypass.setFocus(true)     
                m.btngrp.setFocus(false)
                handled = true

            end if

                handled = true
        end if
        handled = true
end if   

Thank you.

解决方案

Check here.

You should use .setFocus(true) and .hasFocus(), which are available to most renderable nodes such as TextEditBox and Button.

E.g.

if key = "down" then 
    if textBox1.hasFocus() then 
        textBox2.setFocus(true)
    elseif textBox2.hasFocus() then 
        button.setFocus(true)
    end if
end if

if key = "up" then 
    if button.hasFocus() then 
        textBox2.setFocus(true)
    elseif textBox2.hasFocus() then 
        textBox1.setFocus(true)
    end if
end if

这篇关于使用Brightscript通过两个文本框和按钮保持焦点的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆