如何将列表传递给R中的函数? [英] How to pass a list to a function in R?

问题描述

我一直很难找到有关如何将列表传递给R中的函数的信息.

I have been having difficulty finding information about how to pass a list to a function in R.

例如，我以前使用过这种方法

I have used this approach before, e.g.

plot(list(x=1,y=1))

但以下示例给了我一个错误:

but the following example gives me an error:

foo <- function(a, b) c <- a + b
foo(list(a=1,b=1))

Error in foo(list(a = 1, b = 1)) : 
   argument "b" is missing, with no default

此外，?function 不起作用， help('function')不提供有关将列表传递给函数的信息.

Furthermore, ?function doesn't work and help('function') does not provide information on passing a list to a function.

更新

为澄清起见，我理解如何将列表用作单个参数，但是我感到困惑，因为我印象中函数的属性是可以将多个参数作为列表传递.看来这种印象是不正确的.相反，许多功能是专门为处理列表而编写的，如下面的评论和答案所述.

To clarify, I understand how I can use a list as a single argument, but I was confused because I was under the impression that a property of functions was that multiple arguments could be passed as a list. It appears that this impression was incorrect. Rather, many functions are written specifically to handle lists, as described in the comments and answers below.

推荐答案

使用do.call

foo <- function(a, b)  a + b

do.call(foo, list(a=1,b=1))

或者，你可以做

foo <- function(l) l$a + l$b

foo(list(a=1,b=1))

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