为什么这些函数名称放在括号中? [英] Why are these function names in parenthesis?

问题描述

我一直想问这个问题已有一段时间了.这些功能是怎么回事?为什么在括号中使用名称?

I've been meaning to ask this question for a while now. What's going on with these functions? Why are the names in parenthesis?

void        (*think)(gentity_t *self);
void        (*reached)(gentity_t *self);    // movers call this when hitting endpoint
void        (*blocked)(gentity_t *self, gentity_t *other);
void        (*touch)(gentity_t *self, gentity_t *other, trace_t *trace);

推荐答案

在您的示例中，函数名称中的括号表示指向函数地址的变量.如果您不使用括号

In your examples, the parenthesis in function name means that variable of pointing the function address. If you don't use the parenthesis

void * think(gentity_t *self);// equal (void *) think(gentity_t *self); 

这意味着使用以下名称定义函数:think，返回:void *，参数:gentity_t * self;这些是指向函数的变量.

It means the definition of a function with name:think, return: void *, parameter: gentity_t *self; These are the variable of the pointing the functions.

这篇关于为什么这些函数名称放在括号中?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！