我想在Linux上删除多行文本 [英] I want to remove multiple line of text on linux

问题描述

就是这样.
之前:

Just like this.
Before:

1
19:22
abcde

2
19:23

3
19:24
abbff

4
19:25
abbc

之后:

1
19:22
abcde

3
19:24
abbff

4
19:25
abbc

我想删除没有字母的部分，如第2部分.
我认为我应该使用perl或sed.但是我不知道该怎么办.我尝试过这样.但这没用.

I want remove the section having no alphabet like section 2.
I think that I should use perl or sed. But I don't know how to do. I tried like this. But it didn't work.

sed 's/[0-9]\n[0-9]\n%s\n//'

推荐答案

sed用于单独行s/old/new/，仅此.对于其他任何事情，您都应该使用awk:

sed is for doing s/old/new/ on individual lines, that is all. For anything else you should be using awk:

$ awk -v RS= -v ORS='\n\n' '/[[:alpha:]]/' file
1
19:22
abcde

3
19:24
abbff

4
19:25
abbc

上面就是这样:

• RS = 告诉awk输入记录用空白行分隔.
• ORS ='\ n \ n'告诉awk输出记录也必须用空行分隔.
• /[[[:alpha:]]/搜索并打印包含字母字符的记录.

• RS= tells awk the input records are separated by blank lines.
• ORS='\n\n' tells awk the output records must also be separated by blank lines.
• /[[:alpha:]]/ searches for and prints records that contain alphabetic characters.

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