具有通用类型的Scala复制案例类 [英] Scala copy case class with generic type
问题描述
我有两个类 PixelObject
, ImageRefObject
和其他一些类,但这只是这两个类,以简化操作.它们都是包含一个uid的 trait Object
的子类.我需要通用方法,该方法将使用给定的新 uid
复制案例类实例.我之所以需要它,是因为我的任务是创建一个类ObjectRepository,该类将保存 Object
的任何子类的实例,并使用新的 uid
返回它.我的尝试:
I have two classes PixelObject
, ImageRefObject
and some more, but here are just these two classes to simplify things. They all are subclasses of a trait Object
that contains an uid.
I need universal method which will copy a case class instance with a given new uid
. The reason I need it because my task is to create a class ObjectRepository which will save instance of any subclass of Object
and return it with new uid
.
My attempt:
trait Object {
val uid: Option[String]
}
trait UidBuilder[A <: Object] {
def withUid(uid: String): A = {
this match {
case x: PixelObject => x.copy(uid = Some(uid))
case x: ImageRefObject => x.copy(uid = Some(uid))
}
}
}
case class PixelObject(uid: Option[String], targetUrl: String) extends Object with UidBuilder[PixelObject]
case class ImageRefObject(uid: Option[String], targetUrl: String, imageUrl: String) extends Object with UidBuilder[ImageRefObject]
val pix = PixelObject(Some("oldUid"), "http://example.com")
val newPix = pix.withUid("newUid")
println(newPix.toString)
但是出现以下错误:
➜ ~ scala /tmp/1.scala
/tmp/1.scala:9: error: type mismatch;
found : this.PixelObject
required: A
case x: PixelObject => x.copy(uid = Some(uid))
^
/tmp/1.scala:10: error: type mismatch;
found : this.ImageRefObject
required: A
case x: ImageRefObject => x.copy(uid = Some(uid))
^
two errors found
推荐答案
我会坚持使用Seam提出的解决方案.我在几个月前做了同样的事情.例如:
I would stick with the solution proposed by Seam. I have done the same a couple of months ago. For example:
trait Entity[E <: Entity[E]] {
// self-typing to E to force withId to return this type
self: E => def id: Option[Long]
def withId(id: Long): E
}
case class Foo extends Entity[Foo] {
def withId(id:Long) = this.copy(id = Some(id))
}
因此,您不必在实现本身的所有定义中定义方法,而不是为特征的所有实现定义具有匹配项的UuiBuilder.您可能不想每次添加新的实现时都修改UuiBuilder.
So, instead of defining an UuiBuilder with a match for all implementations of your trait, you define the method in your implementation itself. You probably don't want to modify UuiBuilder every time you add a new implementation.
此外,我还建议您使用自定义类型来强制withId()方法的返回类型.
In addition, I would also recommend you to use a self typing to enforce the return type of your withId() method.
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