将CSV文件转换为shapefile-但不希望多边形指向 [英] Converting CSV file to shapefile - but want polygon not points

问题描述

我有一个csv数据框，其坐标为正方形.我已将csv转换为shapefile，但它以四个单独的点进行绘制，并且我希望该图显示一个正方形.

I have a csv dataframe with the coordinates of a square. I have converted the csv into a shapefile, but it plots as four separate points and I want the plot to show a square.

  Shape long lat
1   1.1   43  10
2   1.1   43  13
3   1.1   40  13
4   1.1   40  10

我已将其转换为shapefile并为其指定了坐标参考系统，如下所示:

I have converted it into a shapefile and given it a coordinate reference system as follows:

test <- as.data.frame(read_csv("/Users/alan/Desktop/Test.csv"))
Coord_Ref <- st_crs(3035)
plot_locations_test <- st_as_sf(test, coords = c("long", "lat"), crs =Coord_Ref)

然后我可以使用ggplot绘制shapefile

Then I can plot the shapefile using ggplot

ggplot() +geom_sf(data = plot_locations_test)

我得到这个情节

如何使它填充为正方形而不是单独的点?

How can I make this a filled in square rather than seperate dots?

推荐答案

您需要根据数据点创建一个简单的多边形，并确保形状是封闭的(即第一个点必须与最后一个点相同).您将经度/纬度列转换为矩阵，并将其放在列表中以传递给 st_polygon .

You need to create a simple polygon from the data points, ensuring that the shape is closed (i.e. the first point must be the same as the last point). You convert the longitude / latitude columns to a matrix and put it in a list to pass to st_polygon.

创建多边形后，需要使用 st_sfc 将其转换为sfc:

Once you have created your polygon, you need to convert it to sfc using st_sfc:

test <- as.matrix(rbind(test[,-1], test[1, -1]))

Coord_Ref <- st_crs(3035)
plot_locations_test <- st_polygon(x = list(test))
plot_locations_test <- st_sfc(plot_locations_test, crs = Coord_Ref)
ggplot(plot_locations_test) + geom_sf(fill = "red", alpha = 0.1)

数据

test <- structure(list(Shape = c(1.1, 1.1, 1.1, 1.1), 
                       long = c(43L, 43L, 40L, 40L), 
                       lat = c(10L, 13L, 13L, 10L)), 
                  class = "data.frame", 
                  row.names = c("1", "2", "3", "4"))

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