将geom_line添加到R中的堆叠条形图 [英] Add geom_line to stacked barplot in r

问题描述

我看过类似的话题，但没有发现任何适合我的情况的

I have looked a similar threads but haven't seen anything specific to my situation.

我想在ggplot2的填充条形图中添加geom_line.我有要叠加为向量的值.有没有一种简单的方法可以将所有值都合并到同一数据帧中呢?

I want to add a geom_line to a fill barchart in ggplot2. I have the values I want to superimpose as a vector. Is there a simple way to do this without merging all the values into the same dataframe?

我的代码(如果相关):

my code if relevant:

ggplot(df_region, aes(fill=as.factor(Secondary1), y=Total, x=Year)) + 
  geom_bar(position="fill", stat="identity") + 
  theme(legend.position="bottom") +
  theme(legend.title=element_blank()) +
  labs(y="Percentage of jobs", x = "Year") + scale_fill_manual(values=c("#8DA0CB"   , "#E78AC3"  )) + theme(axis.title.x = element_text( size = 14),axis.title.y = element_text(size =14))

推荐答案

要绘制线条， geom_line 必须具有预先计算的 y 坐标.这可以通过 aggregate 完成，该方法返回一个data.frame.我已经编写了要用作对象的函数，但是可以将其编写为匿名函数.

To plot the line, geom_line must have the y coordinates computed beforehand. This can be done with aggregate, which returns a data.frame. I have written the function to be applied as an object, but it is possible to write it as an anonymous function.

f <- function(x) x[2]/sum(x)
df_line <- aggregate(Total ~ Year, df_region, f)

然后，在 geom_line 中设置 inherit.aes = FALSE .

ggplot(data=df_region, aes(x=Year, y=Total, fill=as.factor(Secondary1))) + 
  geom_bar(position="fill", stat="identity") +
  geom_line(data = df_line, mapping = aes(x = Year, y = Total), color = "red", inherit.aes = FALSE) + 
  theme(legend.position="bottom") +
  theme(legend.title=element_blank()) +
  labs(y="Percentage of jobs", x = "Year") + 
  scale_fill_manual(values=c("#8DA0CB", "#E78AC3")) + 
  theme(axis.title.x = element_text(size = 14),
        axis.title.y = element_text(size = 14))

测试数据

set.seed(2020)
df_region <- data.frame(Year = rep(2011:2019, each = 2),
                        Secondary1 = rep(c("a", "b"), length(2011:2019)),
                        Total = sample(10, 18, TRUE))

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