散点图无法从数据中识别列名称 [英] Scatterpie doesn't recognize column name from data
问题描述
我想使用 scatterpie 绘制8个数据点.但是，该函数抛出一个错误，即找不到具有y坐标值的列所对应的对象.
我的数据
库(tidyverse)图书馆(散点图)my_df<-结构(list(day_in_july = 13:20，yes_and_yes = c(0.611814345991561，0.574750830564784、0.593323216995448、0.610539845758355、0.650602409638554，0.57429718875502、0.575971731448763、0.545454545454545)，yes_but_no = c(0.388185654008439，0.425249169435216、0.406676783004552、0.389460154241645、0.349397590361446，0.42570281124498、0.424028268551237、0.454545454545455))，行名称= c(NA，-8L)，类= c("tbl_df"，"tbl"，"data.frame"))>my_df###小标题:8 x 3## day_in_july yes_and_yes yes_but_no##< int>< dbl>< dbl>## 1 13 0.612 0.388## 2 14 0.575 0.425## 3 15 0.593 0.407## 4 16 0.611 0.389## 5 17 0.651 0.349## 6 18 0.574 0.426## 7 19 0.576 0.424## 8 20 0.545 0.455 使用散点图绘制数据失败
我遵循了
但这不是我想要的.相反，我希望每个饼图的中心处的y值对应于该特定饼图的'yes_but_no'比例
之所以出现此问题，是因为您为 y 映射&馅饼列.
geom_scatterpie 的基础代码进行了一些数据操作，以将数据帧旋转/收集(取决于您的tidyr软件包的术语)，以使其为长格式，因此 yes_but_no 列ggplot尝试绘制最终数据时，它不再单独存在.以下将起作用:
my_df $ y<-my_df $ yes_but_no#创建重复列ggplot()+geom_scatterpie(aes(x = day_in_july，y = y)，数据= my_df，cols = colnames(my_df)[2:3]) 为获得更好的外观，您可以在隔开y位置的同时应用相等的坐标:
ggplot()+geom_scatterpie(aes(x = day_in_july，y = y * 100)，#空间y位置向外数据= my_df，cols = colnames(my_df)[2:3])+scale_y_continuous(name =是但没有"，标签=函数(x)x/100)+#保持原始y标签coord_fixed()
I want to plot 8 data points using scatterpie. However, the function is throwing an error that it can't find the object corresponding to the column with values for y-coordinates.
My Data
library(tidyverse)
library(scatterpie)
my_df <- structure(list(day_in_july = 13:20, yes_and_yes = c(0.611814345991561,
0.574750830564784, 0.593323216995448, 0.610539845758355, 0.650602409638554,
0.57429718875502, 0.575971731448763, 0.545454545454545), yes_but_no = c(0.388185654008439,
0.425249169435216, 0.406676783004552, 0.389460154241645, 0.349397590361446,
0.42570281124498, 0.424028268551237, 0.454545454545455)), row.names = c(NA,
-8L), class = c("tbl_df", "tbl", "data.frame"))
> my_df
## # A tibble: 8 x 3
## day_in_july yes_and_yes yes_but_no
## <int> <dbl> <dbl>
## 1 13 0.612 0.388
## 2 14 0.575 0.425
## 3 15 0.593 0.407
## 4 16 0.611 0.389
## 5 17 0.651 0.349
## 6 18 0.574 0.426
## 7 19 0.576 0.424
## 8 20 0.545 0.455
Plotting the data using scatterpie fails
I followed the code from the documentation, but it still isn't working for me.
ggplot() +
geom_scatterpie(aes(x = day_in_july, y = yes_but_no),
data = my_df,
cols = colnames(my_df)[2:3])
## Error in FUN(X[[i]], ...) : object 'yes_but_no' not found
I've tried converting from tibble to a data.frame beforehand, but didn't solve the problem.
By the way, setting y as a constant (e.g., 2) works:
ggplot() +
geom_scatterpie(aes(x = day_in_july, y = 2),
data = my_df,
cols = colnames(my_df)[2:3]) +
coord_fixed()
But this is not what I want. Rather, I want the y-value each pie chart is centered at to correspond to the 'yes_but_no' proportion for that specific pie chart
The problem arises because you recycled the same column for the y mapping & pie columns.
The underlying code for geom_scatterpie does some data manipulations to pivot/gather (depending on the terminology of your tidyr package) the dataframe to long form, so the yes_but_no column no longer exists on its own by the time ggplot tries to plot the finalised data. The following would work:
my_df$y <- my_df$yes_but_no # create a duplicate column
ggplot() +
geom_scatterpie(aes(x = day_in_july, y = y),
data = my_df,
cols = colnames(my_df)[2:3])
For better appearance, you can apply equal coordinates while spacing out the y positions:
ggplot() +
geom_scatterpie(aes(x = day_in_july, y = y*100), # space y positions out
data = my_df,
cols = colnames(my_df)[2:3]) +
scale_y_continuous(name = "yes but no",
labels = function(x) x/100) + # maintain original y labels
coord_fixed()
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