是否可以保证将结果遍历在Perl中排序? [英] Is there any guarantee that results of globbing will be sorted in Perl?

问题描述

是否可以保证将从glob返回的文件名数组(例如< *> )排序?

Is there any guarantee that the array of filenames returned from a glob (e.g. <*>) will be sorted?

我找不到文档中提到的一种排序方式或另一种排序方式 ，但在我尝试过的每个目录中似乎都是这种情况.

I can't find that sorting is mentioned one way or the other in the documentation, but it seems to be the case in every directory I've tried it on.

我正在谈论使用这种语法:

I'm talking about using this syntax:

@files = <*>;

如果我需要对文件进行排序，以下内容是否多余?

If I need the files to be sorted, would the below be redundant?

@files = sort(<*>);

推荐答案

在Perl 5.6.0及更高版本中，文件名进行了排序:

In Perl 5.6.0 and newer, filenames are sorted:

从v5.6.0开始，此运算符使用标准实施File :: Glob扩展名.

Beginning with v5.6.0, this operator is implemented using the standard File::Glob extension.

-针对glob的perldoc

默认情况下，路径名已排序ASCII升序.

By default, the pathnames are sorted in ascending ASCII order.

-用于File :: Glob的perldoc

有一个收获:

默认情况下，假定文件名是区分大小写

By default, file names are assumed to be case sensitive

-针对File :: Glob的perldoc

说了这么多，您可以更改此行为，以区分大小写使用

Having said all that, you can change this behavior to sort case-insensitively with

use File::Glob qw(:globally :nocase);

请注意::globally自5.6.0起是多余的，但这也适用于旧版本.

Note that :globally is redundant since 5.6.0, but this will work on older versions as well.

或者，如果您只想做一个不区分大小写的glob:

Alternately, if you just want to do a single glob with case-insensitivity:

use File::Glob ':glob';

@files = bsd_glob('*', GLOB_NOCASE);

这篇关于是否可以保证将结果遍历在Perl中排序?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！