C ++-编译多个文件 [英] C++ - Compiling multiple files

问题描述

我正在学习看起来很强大的makefile工具，并且由于我有4个不同的mains和其中3个mains的通用类而试图弄清楚如何使其工作.

I was learning about the makefile tool which seems very powerful, and was trying to figure out how to make it work since I have 4 different mains and a common class for 3 of them.

我想要得到的是:

线性: g ++ -o linear linear.cpp

Linear5: g ++ -o linear5 linear5.cpp Contenidor.cpp Contenidor.h

对数: g ++ -o logarithmic logarithmic.cpp Contenidor.cpp Contenidor.h

常量: g ++ -o常量constant.cpp Contenidor.cpp Contenidor.h

使用以下Makefile代码:

With the following Makefile code:

all: linear5 linear logarithmic constant

linear5: linear5.o
    g++ -o linear5 linear5.o

linear5.o: linear5.cpp
    g++ -cpp linear5.cpp

Contenidor.o: Contenidor.cpp
    g++ -cpp Contenidor.cpp

linear: linear.o Contenidor.o
    g++ -o linear linear.o Contenidor.o

linear.o: linear.cpp
    g++ -cpp linear.cpp

logarithmic: logarithmic.o Contenidor.o
    g++ -o logarithmic logarithmic.o Contenidor.o

logarithmic.o: logarithmic.cpp
    g++ -cpp logarithmic.cpp

constant: constant.o Contenidor.o
    g++ -std=gnu++0x -o constant constant.o Contenidor.o

constant.o: constant.cpp
    g++ -cpp constant.cpp

clean:
    rm *.o

但是当我尝试执行make命令时会弹出错误消息:

But an error pops out when I try execute the make command:

g++ -cpp linear5.cpp
g++ -o linear5 linear5.o
g++: linear5.o: No such file or directory
g++: no input files

推荐答案

问题在于执行两步编译的方式:您应该更改的每个实例

The problem is in the way you perform two-step compilation: you should change every instance of

file.o: file.cpp
    g++ -cpp file.cpp

进入:

file.o: file.cpp
    g++ -c -o file.o file.cpp

这样，您告诉g ++仅编译( -c )而不链接文件；输出将是一个目标文件，尽管如此，您仍然必须使用 -o 指定其名称.

This way, you tell g++ to just compile (-c) and not link your file; the output will be an object file, you still have to specify its name with -o though.

然后，可以在以后的步骤中使用目标文件.

Then, the object file can be used in later steps.

这篇关于C ++-编译多个文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！